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The conductivity of the dilute NaCl solution should be substantially higher than that of DI water because of the much higher number of ions present in the NaCl solution. Those ions are produced by the dissociation of NaCl when it dissolves in water, as represented by the following balanced equation: NaCl (s) →Na+ (aq) + Cl (aq) Note that each formula unit of NaCl dissociates to produce one sodium ion and one chloride ion. This relationship continues to the mole scale; in other words, one mole of NaCl dissociates to produce one mole of sodium ions and one mole of chloride ions. Your original solution was prepared with (approximately) 0.010 moles of NaCl. Based on this quantity and the balanced equation above, determine the number of moles of Nat and Cl in the solution, as well as the total number of ions present. Moles Nat: Moles Cl: Total moles of ions:

The conductivity of the dilute NaCl solution should be substantially higher than that of DI water because of the much higher number of ions present in the NaCl solution. Those ions are produced by the dissociation of NaCl when it dissolves in water, as represented by the following balanced equation: NaCl (s) →Na+ (aq) + Cl (aq) Note that each formula unit of NaCl dissociates to produce one sodium ion and one chloride ion. This relationship continues to the mole scale; in other words, one mole of NaCl dissociates to produce one mole of sodium ions and one mole of chloride ions. Your original solution was prepared with (approximately) 0.010 moles of NaCl. Based on this quantity and the balanced equation above, determine the number of moles of Nat and Cl in the solution, as well as the total number of ions present. Moles Nat: Moles Cl: Total moles of ions:

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Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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The conductivity of the dilute NaCl solution should be substantially higher than that of DI water because of the much higher number of ions present in the NaCl solution. Those ions are produced by the dissociation of NaCl when it dissolves in water, as represented by the following balanced equation: NaCl (s) →Nat (aq) + Cl- (aq) Note that each formula unit of NaCl dissociates to produce one sodium ion and one chloride ion. This relationship continues to the mole scale; in other words, one mole of NaCl dissociates to produce one mole of sodium ions and one mole of chloride ions. Your original solution was prepared with (approximately) 0.010 moles of NaCl. Based on this quantity and the balanced equation above, determine the number of moles of Nat and Cl in the solution, as well as the total number of ions present. Moles Nat: Moles Cl: Total moles of ions:
Transcribed Image Text:The conductivity of the dilute NaCl solution should be substantially higher than that of DI water because of the much higher number of ions present in the NaCl solution. Those ions are produced by the dissociation of NaCl when it dissolves in water, as represented by the following balanced equation: NaCl (s) →Nat (aq) + Cl- (aq) Note that each formula unit of NaCl dissociates to produce one sodium ion and one chloride ion. This relationship continues to the mole scale; in other words, one mole of NaCl dissociates to produce one mole of sodium ions and one mole of chloride ions. Your original solution was prepared with (approximately) 0.010 moles of NaCl. Based on this quantity and the balanced equation above, determine the number of moles of Nat and Cl in the solution, as well as the total number of ions present. Moles Nat: Moles Cl: Total moles of ions:
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