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A 50.0 mL portion of 0.500 M NAOH was diluted to 323.1 mL. What is the new molarity? Enter your answer in the provided box. M

A 50.0 mL portion of 0.500 M NAOH was diluted to 323.1 mL. What is the new molarity? Enter your answer in the provided box. M

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Dilution and Molarity Calculation** In this exercise, we are given a scenario where a 50.0 mL portion of a 0.500 M NaOH solution is diluted to a final volume of 323.1 mL. The task is to find the new molarity of the diluted solution. ### Problem Statement * A 50.0 mL portion of 0.500 M NaOH was diluted to 323.1 mL. What is the new molarity? Enter your answer in the provided box. ### Solution Approach To solve this problem, we will use the dilution equation, which is expressed as: \[ C_1V_1 = C_2V_2 \] Where: - \( C_1 \) is the initial concentration (0.500 M) - \( V_1 \) is the initial volume (50.0 mL) - \( C_2 \) is the final concentration (which we need to find) - \( V_2 \) is the final volume (323.1 mL) Rearranging the equation to solve for \( C_2 \): \[ C_2 = \frac{C_1V_1}{V_2} \] Substitute the given values: \[ C_2 = \frac{0.500 \, \text{M} \times 50.0 \, \text{mL}}{323.1 \, \text{mL}} \] Calculate \( C_2 \) to find the new molarity. This method allows us to understand how the concentration of a solution changes when additional solvent is added.
Transcribed Image Text:**Dilution and Molarity Calculation** In this exercise, we are given a scenario where a 50.0 mL portion of a 0.500 M NaOH solution is diluted to a final volume of 323.1 mL. The task is to find the new molarity of the diluted solution. ### Problem Statement * A 50.0 mL portion of 0.500 M NaOH was diluted to 323.1 mL. What is the new molarity? Enter your answer in the provided box. ### Solution Approach To solve this problem, we will use the dilution equation, which is expressed as: \[ C_1V_1 = C_2V_2 \] Where: - \( C_1 \) is the initial concentration (0.500 M) - \( V_1 \) is the initial volume (50.0 mL) - \( C_2 \) is the final concentration (which we need to find) - \( V_2 \) is the final volume (323.1 mL) Rearranging the equation to solve for \( C_2 \): \[ C_2 = \frac{C_1V_1}{V_2} \] Substitute the given values: \[ C_2 = \frac{0.500 \, \text{M} \times 50.0 \, \text{mL}}{323.1 \, \text{mL}} \] Calculate \( C_2 \) to find the new molarity. This method allows us to understand how the concentration of a solution changes when additional solvent is added.
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