The equivalent circuit of a 22KVA, 11700/520 V, 60HZ, single-phase loaded transformer when referred to its low-voltage side is given. Find the percent voltage regulation of this transformer under this loading conditions. 4= 40.25 22.5 1.0 + j1.25 e Vs = 4 Ko j6.1 Ko 381/0° Select one: O a. %VR = -6.0 %
The equivalent circuit of a 22KVA, 11700/520 V, 60HZ, single-phase loaded transformer when referred to its low-voltage side is given. Find the percent voltage regulation of this transformer under this loading conditions. 4= 40.25 22.5 1.0 + j1.25 e Vs = 4 Ko j6.1 Ko 381/0° Select one: O a. %VR = -6.0 %
Introductory Circuit Analysis (13th Edition)
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Author:Robert L. Boylestad
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![The equivalent circuit of a 22KVA, 11700/520 V, 60HZ, single-phase loaded transformer
when referred to its low-voltage side is given.
Find the percent voltage regulation of this transformer under this loading conditions.
of
L= 40.25 / 22.5%
1.0 + j1.25 o
Vs =
4 Ko
&j6.1 Ko
381 0 vl
Select one:
O a. %VR = -6.0 %
O b. None
O c. %VR = 6.0 %
O d. %VR = 11.35 %](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc0b79156-7a9f-4c44-993c-598120e4da6e%2F40fb24cc-7333-48eb-abdc-237323b4bb8e%2F45i8qs6_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The equivalent circuit of a 22KVA, 11700/520 V, 60HZ, single-phase loaded transformer
when referred to its low-voltage side is given.
Find the percent voltage regulation of this transformer under this loading conditions.
of
L= 40.25 / 22.5%
1.0 + j1.25 o
Vs =
4 Ko
&j6.1 Ko
381 0 vl
Select one:
O a. %VR = -6.0 %
O b. None
O c. %VR = 6.0 %
O d. %VR = 11.35 %
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