The equipment used for aviation communications emits high-frequency radiowave energy with a wavelength of 0.700 km. What is the energy of exactly one photon of this radiowave radiation? E = What is the energy of one mole of this radiowave radiation? J/mol E =
The equipment used for aviation communications emits high-frequency radiowave energy with a wavelength of 0.700 km. What is the energy of exactly one photon of this radiowave radiation? E = What is the energy of one mole of this radiowave radiation? J/mol E =
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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![**Title: Energy Calculation of Radiowave Photons in Aviation Communications**
**Introduction:**
In the field of aviation communications, specialized equipment emits high-frequency radiowave energy. This exercise focuses on calculating the energy associated with radiowaves, which possess a wavelength of 0.700 km.
**Problem Statements:**
1. **Photon Energy Calculation:**
- Calculate the energy, \( E \), of precisely one photon of this radiowave radiation.
- Equation: \( E = \) _________ J
2. **Mole Energy Calculation:**
- Determine the energy, \( E \), contained in one mole of this radiowave radiation.
- Equation: \( E = \) _________ J/mol
**Explanation:**
- The energy of a photon can be determined using the equation:
\[
E = \frac{h \cdot c}{\lambda}
\]
where \( E \) is the energy in joules, \( h \) is Planck’s constant (\(6.626 \times 10^{-34} \, \text{J} \cdot \text{s}\)), \( c \) is the speed of light (\(3.00 \times 10^8 \, \text{m/s}\)), and \( \lambda \) is the wavelength in meters.
- To find the energy per mole, multiply the energy of one photon by Avogadro’s number (\(6.022 \times 10^{23} \, \text{mol}^{-1}\)).
**Note:** Ensure that the wavelength is converted from kilometers to meters before performing the calculations.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F245e0eb4-5097-4578-8f56-633b47cf5980%2F743fcf71-5ef6-4ea5-a266-649e890ebd5d%2Fomn3dom_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Title: Energy Calculation of Radiowave Photons in Aviation Communications**
**Introduction:**
In the field of aviation communications, specialized equipment emits high-frequency radiowave energy. This exercise focuses on calculating the energy associated with radiowaves, which possess a wavelength of 0.700 km.
**Problem Statements:**
1. **Photon Energy Calculation:**
- Calculate the energy, \( E \), of precisely one photon of this radiowave radiation.
- Equation: \( E = \) _________ J
2. **Mole Energy Calculation:**
- Determine the energy, \( E \), contained in one mole of this radiowave radiation.
- Equation: \( E = \) _________ J/mol
**Explanation:**
- The energy of a photon can be determined using the equation:
\[
E = \frac{h \cdot c}{\lambda}
\]
where \( E \) is the energy in joules, \( h \) is Planck’s constant (\(6.626 \times 10^{-34} \, \text{J} \cdot \text{s}\)), \( c \) is the speed of light (\(3.00 \times 10^8 \, \text{m/s}\)), and \( \lambda \) is the wavelength in meters.
- To find the energy per mole, multiply the energy of one photon by Avogadro’s number (\(6.022 \times 10^{23} \, \text{mol}^{-1}\)).
**Note:** Ensure that the wavelength is converted from kilometers to meters before performing the calculations.
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