The equilibrium constants for the following reaction at 600°C and 900°C are 3.9 x 10-1 and 1.34 x 103 respectively. • Calculate AH° for the reaction in kJ. H2(g) + CO2(g) <-->CO(g) + H2O(g) OA. +39.0 O B. -161 O C. -35.0 O D. +161 O E. -49.9
The equilibrium constants for the following reaction at 600°C and 900°C are 3.9 x 10-1 and 1.34 x 103 respectively. • Calculate AH° for the reaction in kJ. H2(g) + CO2(g) <-->CO(g) + H2O(g) OA. +39.0 O B. -161 O C. -35.0 O D. +161 O E. -49.9
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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### Question 13
The equilibrium constants for the following reaction at 600°C and 900°C are 3.9 x 10⁻¹ and 1.34 x 10⁻³ respectively.
**Calculate ΔH⁰ for the reaction in kJ.**
\[ \text{H}_2(g) + \text{CO}_2(g) \leftrightarrow \text{CO}(g) + \text{H}_2\text{O}(g) \]
Options:
- A. +39.0
- B. -161
- C. -35.0
- D. +161
- E. -49.9
---
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Transcribed Image Text:---
### Question 13
The equilibrium constants for the following reaction at 600°C and 900°C are 3.9 x 10⁻¹ and 1.34 x 10⁻³ respectively.
**Calculate ΔH⁰ for the reaction in kJ.**
\[ \text{H}_2(g) + \text{CO}_2(g) \leftrightarrow \text{CO}(g) + \text{H}_2\text{O}(g) \]
Options:
- A. +39.0
- B. -161
- C. -35.0
- D. +161
- E. -49.9
---
**Note**: Moving to another question will save this response.
---
In this example, there are no graphs or diagrams to explain.
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