The equilibrium constant of a reaction is found to fit the expression 1176 2.1 x 107 + T/K (T/K)² In Kp == - 2.40 between 400 K and 500 K. Calculate the standard reaction enthalpy and standard reac- tion entropy at 450 K.
The equilibrium constant of a reaction is found to fit the expression 1176 2.1 x 107 + T/K (T/K)² In Kp == - 2.40 between 400 K and 500 K. Calculate the standard reaction enthalpy and standard reac- tion entropy at 450 K.
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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![The equilibrium constant of a reaction is found to fit the expression
\[
\ln K_p = -2.40 - \frac{1176}{T/\text{K}} + \frac{2.1 \times 10^7}{(T/\text{K})^2}
\]
between 400 K and 500 K. Calculate the standard reaction enthalpy and standard reaction entropy at 450 K.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9d6b1f03-b4bd-4f60-ae23-d8256607755b%2F311dbbd8-a0ca-4773-9e7b-466a309a1f2c%2F819wlma_processed.png&w=3840&q=75)
Transcribed Image Text:The equilibrium constant of a reaction is found to fit the expression
\[
\ln K_p = -2.40 - \frac{1176}{T/\text{K}} + \frac{2.1 \times 10^7}{(T/\text{K})^2}
\]
between 400 K and 500 K. Calculate the standard reaction enthalpy and standard reaction entropy at 450 K.
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