The equilibrium constant (Kc) for the following reaction is 6.7 x 10-10 at 630 °C. N2(s) + O2(g) 2NO(g) What is the equilibrium constant for the reaction below at the temperature? ½N2(s) + ½O2(g) =NO(g)

The equilibrium constant (Kc) for the following reaction is 6.7 x 10-10 at 630 °C. N2(s) + O2(g) 2NO(g) What is the equilibrium constant for the reaction below at the temperature? ½N2(s) + ½O2(g) =NO(g)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

The equilibrium constant (Kc) for the following reaction is 6.7 x 10-10 at 630 °C.
N2(s) + O2(g) 2NO(g)
What is the equilibrium constant for the reaction below at the
temperature?
½N2(s) + ½O2(g) =NO(g)
4.5 x 10-19
4 x 10-10
1.8 x 10-5
А.
В.
С.
D.
2.6 x 10-5

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