The equilibrium constant K for the reaction H₂(g) + - Br₂(g) = 2 HBr (g) is 2.180 x 106 Part: 0 / 2 Part 1 of 2 at 730.0 °C. Starting with 2.20 moles of HBr in a 19.4 L reaction vessel, calculate the concentrations of H₂, Br₂, and HBr at equilibrium. Be sure each of your answer entries has the correct number of significant digits. [H₂] = 2.92 × 10 Br₂] = 2.92 × 10 M M x10 X
The equilibrium constant K for the reaction H₂(g) + - Br₂(g) = 2 HBr (g) is 2.180 x 106 Part: 0 / 2 Part 1 of 2 at 730.0 °C. Starting with 2.20 moles of HBr in a 19.4 L reaction vessel, calculate the concentrations of H₂, Br₂, and HBr at equilibrium. Be sure each of your answer entries has the correct number of significant digits. [H₂] = 2.92 × 10 Br₂] = 2.92 × 10 M M x10 X
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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HBr=.....M
![The equilibrium constant K for the reaction
С
H₂(g) + Br₂(g) = 2 HBr (g)
is 2.180 × 106 at 730.0 °C. Starting with 2.20 moles of HBr in a 19.4 L reaction vessel, calculate the concentrations of H₂, Br₂, and HBr at equilibrium.
Part: 0 / 2
Part 1 of 2
Be sure each of your answer entries has the correct number of significant digits.
[H₂]
[Br₂]
= 2.92 × 10
= 2.92 × 10
M
M
x10
X
Ś](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3f33cc2f-0221-41a8-a3a2-cc96bc7960a2%2Fec1f2b22-f707-43a0-94a5-a3532acf7e7f%2Fxs8xj4_processed.png&w=3840&q=75)
Transcribed Image Text:The equilibrium constant K for the reaction
С
H₂(g) + Br₂(g) = 2 HBr (g)
is 2.180 × 106 at 730.0 °C. Starting with 2.20 moles of HBr in a 19.4 L reaction vessel, calculate the concentrations of H₂, Br₂, and HBr at equilibrium.
Part: 0 / 2
Part 1 of 2
Be sure each of your answer entries has the correct number of significant digits.
[H₂]
[Br₂]
= 2.92 × 10
= 2.92 × 10
M
M
x10
X
Ś
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