The equilibrium constant, K, for the following reaction is 1.57 at 600 K: CO(g) + C(g) COCI,(g) Calculate the equilibrium partial pressures of all species when cO and Cl. each at an intitial partial pressure of 1.06 atm, are introduced into an evacuated vessel at 600 K. Pco atm atm = Pcoc, atm

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**Equilibrium Study: Reaction of CO and Cl₂**

For the chemical reaction:

\[ \text{CO(g) + Cl}_2\text{(g)} \rightleftharpoons \text{COCl}_2\text{(g)} \]

The equilibrium constant, \( K_p \), is given as 1.57 at a temperature of 600 K.

**Objective:**

Determine the equilibrium partial pressures of all species involved when CO and Cl₂ are each introduced at an initial partial pressure of 1.06 atm into an evacuated vessel maintained at 600 K.

**Procedure:**

1. **Determine Initial Conditions:**
   - **Initial partial pressures:**
     - \[ P_{\text{CO}} = 1.06 \, \text{atm} \]
     - \[ P_{\text{Cl}_2} = 1.06 \, \text{atm} \]
     - \[ P_{\text{COCl}_2} = 0 \, \text{atm} \]

2. **Set Up Equilibrium Expression:**
   - Let \( x \) be the change in pressure due to the formation of COCl₂.
   - Equilibrium pressures will be:
     - \[ P_{\text{CO}} = 1.06 - x \]
     - \[ P_{\text{Cl}_2} = 1.06 - x \]
     - \[ P_{\text{COCl}_2} = x \]

3. **Apply the Equilibrium Constant:**
   - \[ K_p = \frac{P_{\text{COCl}_2}}{P_{\text{CO}} \cdot P_{\text{Cl}_2}} = \frac{x}{(1.06 - x)(1.06 - x)} = 1.57 \]

4. **Solve for \( x \) to find Equilibrium Pressures:**

\[ P_{\text{CO}} = \]
\[ P_{\text{Cl}_2} = \]
\[ P_{\text{COCl}_2} = \]

**Note:** Insert calculated values for the actual equilibrium pressures to complete the exercise.
Transcribed Image Text:**Equilibrium Study: Reaction of CO and Cl₂** For the chemical reaction: \[ \text{CO(g) + Cl}_2\text{(g)} \rightleftharpoons \text{COCl}_2\text{(g)} \] The equilibrium constant, \( K_p \), is given as 1.57 at a temperature of 600 K. **Objective:** Determine the equilibrium partial pressures of all species involved when CO and Cl₂ are each introduced at an initial partial pressure of 1.06 atm into an evacuated vessel maintained at 600 K. **Procedure:** 1. **Determine Initial Conditions:** - **Initial partial pressures:** - \[ P_{\text{CO}} = 1.06 \, \text{atm} \] - \[ P_{\text{Cl}_2} = 1.06 \, \text{atm} \] - \[ P_{\text{COCl}_2} = 0 \, \text{atm} \] 2. **Set Up Equilibrium Expression:** - Let \( x \) be the change in pressure due to the formation of COCl₂. - Equilibrium pressures will be: - \[ P_{\text{CO}} = 1.06 - x \] - \[ P_{\text{Cl}_2} = 1.06 - x \] - \[ P_{\text{COCl}_2} = x \] 3. **Apply the Equilibrium Constant:** - \[ K_p = \frac{P_{\text{COCl}_2}}{P_{\text{CO}} \cdot P_{\text{Cl}_2}} = \frac{x}{(1.06 - x)(1.06 - x)} = 1.57 \] 4. **Solve for \( x \) to find Equilibrium Pressures:** \[ P_{\text{CO}} = \] \[ P_{\text{Cl}_2} = \] \[ P_{\text{COCl}_2} = \] **Note:** Insert calculated values for the actual equilibrium pressures to complete the exercise.
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