The equilibrium constant for the dissociation of ethanol into ethylene and water C₂H5OH(g) — C₂H4 (g) + H₂O(g) is 0.6246 at 351 K (the normal boiling point of ethanol). Calculate the degree of dissociation a at this temperature. The reaction does not normally occur (in the absence of a catalyst) because it is too slow. If it did, it would be a major problem for the distillers of alcoholic beverages. ? a data: K, T, P | C E C₂H5OH (g) 1 1- x C₂H₂(g) + H₂O(g) 0 0 x K = 1-x (1) + x 1/23

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The equilibrium constant for the dissociation of ethanol into
ethylene and water
? α
data: K, T, P
GC2.3.1
C₂H5OH(g) · C₂H₂(g) + H₂O(g)
is 0.6246 at 351 K (the normal boiling point of ethanol).
Calculate the degree of dissociation a at this temperature.
The reaction does not normally occur (in the absence of a
catalyst) because it is too slow. If it did, it would be a major
problem for the distillers of alcoholic beverages.
|
C
E
C₂H5OH(g)
1
-X
P⁰= 12hm
:
1.x
=
C₂H4 (g) + H₂O(g)
0
0
火
K =
(1)
x 2
1-x
+ x
1/23
Transcribed Image Text:The equilibrium constant for the dissociation of ethanol into ethylene and water ? α data: K, T, P GC2.3.1 C₂H5OH(g) · C₂H₂(g) + H₂O(g) is 0.6246 at 351 K (the normal boiling point of ethanol). Calculate the degree of dissociation a at this temperature. The reaction does not normally occur (in the absence of a catalyst) because it is too slow. If it did, it would be a major problem for the distillers of alcoholic beverages. | C E C₂H5OH(g) 1 -X P⁰= 12hm : 1.x = C₂H4 (g) + H₂O(g) 0 0 火 K = (1) x 2 1-x + x 1/23
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