The equilibrium bond length for HBr is 1.66 Å. (A) Calculate the value of the rotational constant for HBr, assuming that a molecule of the compound behaves as a rigid rotor whose length is equal to the HBr equilibrium bond length. (B) Compute the rotational molecular partition function for HBr at a temperature of 800 K to four significant digits. (C) Determine the most populated rotational state of HBr at 800 K. Assume that the atomic masses are the average atomic masses, (i.e., atomic weights).

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17.12 The equilibrium bond length for HBr is 1.66 Å.
(A) Calculate the value of the rotational constant for
HBr, assuming that a molecule of the compound
behaves as a rigid rotor whose length is equal to the
HBr equilibrium bond length.
(B) Compute the rotational molecular partition
function for HBr at a temperature of 800 K to four
significant digits.
(C) Determine the most populated rotational state
of HBr at 800 K. Assume that the atomic masses are
the average atomic masses, (i.e., atomic weights).
Transcribed Image Text:17.12 The equilibrium bond length for HBr is 1.66 Å. (A) Calculate the value of the rotational constant for HBr, assuming that a molecule of the compound behaves as a rigid rotor whose length is equal to the HBr equilibrium bond length. (B) Compute the rotational molecular partition function for HBr at a temperature of 800 K to four significant digits. (C) Determine the most populated rotational state of HBr at 800 K. Assume that the atomic masses are the average atomic masses, (i.e., atomic weights).
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