The equations ze + uz – cos(v) – 2 = 0 and u cos(y) + 4z2v – 5yz2 – 1= 0 can be solved for (u,v) as functions of (xy.z) near the point P(xy,zu,v)=(2,0,1,1,0). Find ()zy at (2,0,1). (zey + uz – cos(v) -2 = 0 ve u cos(y) + 4z'v – 5yz? – 1 = 0 denklemleri P(xy.zuv)=(2,0,1,1,0) noktası civarında (xy.z)'nin fonksiyonu olmak üzere (u,v) için çözümlüdür. (2,0,1) noktasında ()zy yi hesaplayınız.) Lütfen birini seçin: 00 01 O 0,5 O-0,5 O-1

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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The equations rey +uz – cos(v) – 2 = 0 and u cos(y) + 4a?v – 5yz2 – 1 = 0 can be solved for (u,v) as functions of
(xy,z) near the point P(xy,zu,v)=(2,0,1,1,0). Find ()zy at (2,0,1).
(rey + uz – cos(v) – 2 = 0 ve u cos(y) + 4z?v – 5yz2 – 1 = 0 denklemleri P(xy.z,u,v)=(2,0,1,1,0) noktası civarında
(xy.z)'nin fonksiyonu olmak üzere (u,v) için çözümlüdür. (2,0,1) noktasında ()zy yi hesaplayınız.)
Lütfen birini seçin:
00
01
O 0,5
O-0,5
O-1
Transcribed Image Text:The equations rey +uz – cos(v) – 2 = 0 and u cos(y) + 4a?v – 5yz2 – 1 = 0 can be solved for (u,v) as functions of (xy,z) near the point P(xy,zu,v)=(2,0,1,1,0). Find ()zy at (2,0,1). (rey + uz – cos(v) – 2 = 0 ve u cos(y) + 4z?v – 5yz2 – 1 = 0 denklemleri P(xy.z,u,v)=(2,0,1,1,0) noktası civarında (xy.z)'nin fonksiyonu olmak üzere (u,v) için çözümlüdür. (2,0,1) noktasında ()zy yi hesaplayınız.) Lütfen birini seçin: 00 01 O 0,5 O-0,5 O-1
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