Find the equation of the curve whose y"=y=2 sin¯¹(x) — 4√³ x3y = sin¯¹(x) — ²√³ x — π+4√/336sin ¹(x)4y = sin ¹(x)y =V ³ x62√33X7-√36T+6√//324TπT6X(1-x²)³/2and has a critical point at (227/3).

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Answered: ind the equation of the curve whose y"…

Calculus: Early Transcendentals

8th Edition

ISBN:9781285741550

Author:James Stewart

Publisher:James Stewart

Chapter1: Functions And Models

Section: Chapter Questions

Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...

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ind the equation of the curve whose y" = ○ y=2 sin-¹ (2) — 4³-√3 -1 - O y = y = sin¯¹(x). X sin (x) 4 gin-¹(a) 2√3 3 3 √3 6 X 2√3 7+4√3 6 +6√/3 24 6 TT X (1-22) 3/2 and has a critical point at (,) 1