The equations xe" + uz – cos(v) – 2 = 0 and ucos(y) + 6x²v – 4yz² – 1 = 0 can be solved for (u,v) as functions of (x.y,z) near the point P(x,y,z,u,v)=(2,0,1,1,0). Find ()y at (2,0,1).

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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The equations xe + uz – cos(v) – 2 = 0 and ucos(v) + 6x²v – 4yz? – 1 = 0 can be solved for (u,v) as functions of (x.y,z) near the point P(x,y,z,u,v)=(2,0,1,1,0).
Find ()y at (2,0,1).
O -0,5
01
O 0,5
O-1
00
Transcribed Image Text:The equations xe + uz – cos(v) – 2 = 0 and ucos(v) + 6x²v – 4yz? – 1 = 0 can be solved for (u,v) as functions of (x.y,z) near the point P(x,y,z,u,v)=(2,0,1,1,0). Find ()y at (2,0,1). O -0,5 01 O 0,5 O-1 00
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