The equation of motion and initial conditions governing the vertical position of a vertical spring-mass system are given below. Transform this equation into a system of 1st order ODEs and solve the system using MATLAB's ode45 function. Provide a plot of y vs. t from 0 to 2 seconds. mj = −k(y – y) – mg y(0) = 1 m j(0) =4m/s k = 100 N/m m = 2 kg g = 9.81 m/s² Yo = 1m

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### Equation of Motion for a Vertical Spring-Mass System

The objective is to transform the given equation of motion into a system of first-order ordinary differential equations (ODEs) and solve it using MATLAB's `ode45` function. Then, provide a plot of displacement \( y \) versus time \( t \) from 0 to 2 seconds.

**Equation of Motion:**

\[ m\ddot{y} = -k(y - y_0) - mg \]

**Initial Conditions:**

- \( y(0) = 1 \, \text{m} \)
- \( \dot{y}(0) = 4 \, \text{m/s} \)

**Given Parameters:**

- Spring constant, \( k = 100 \, \text{N/m} \)
- Mass, \( m = 2 \, \text{kg} \)
- Acceleration due to gravity, \( g = 9.81 \, \text{m/s}^2 \)
- Initial position, \( y_0 = 1 \, \text{m} \)

### Task:

- Transform the second-order ODE into a system of first-order ODEs.
- Utilize MATLAB's `ode45` for solving the system.
- Graph \( y \) against \( t \) for the duration of 0 to 2 seconds.

The solution involves converting the second-order ODE into a system by defining:

1. \( y_1 = y \)
2. \( y_2 = \dot{y} \)

This yields:

\[ \dot{y}_1 = y_2 \]
\[ \dot{y}_2 = \frac{-k(y_1 - y_0) - mg}{m} \]

With these equations, code up the system in MATLAB, use the `ode45` solver, and plot \( y_1 \) against \( t \).
Transcribed Image Text:### Equation of Motion for a Vertical Spring-Mass System The objective is to transform the given equation of motion into a system of first-order ordinary differential equations (ODEs) and solve it using MATLAB's `ode45` function. Then, provide a plot of displacement \( y \) versus time \( t \) from 0 to 2 seconds. **Equation of Motion:** \[ m\ddot{y} = -k(y - y_0) - mg \] **Initial Conditions:** - \( y(0) = 1 \, \text{m} \) - \( \dot{y}(0) = 4 \, \text{m/s} \) **Given Parameters:** - Spring constant, \( k = 100 \, \text{N/m} \) - Mass, \( m = 2 \, \text{kg} \) - Acceleration due to gravity, \( g = 9.81 \, \text{m/s}^2 \) - Initial position, \( y_0 = 1 \, \text{m} \) ### Task: - Transform the second-order ODE into a system of first-order ODEs. - Utilize MATLAB's `ode45` for solving the system. - Graph \( y \) against \( t \) for the duration of 0 to 2 seconds. The solution involves converting the second-order ODE into a system by defining: 1. \( y_1 = y \) 2. \( y_2 = \dot{y} \) This yields: \[ \dot{y}_1 = y_2 \] \[ \dot{y}_2 = \frac{-k(y_1 - y_0) - mg}{m} \] With these equations, code up the system in MATLAB, use the `ode45` solver, and plot \( y_1 \) against \( t \).
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