%%% plotting the solution y for each gamma figure; = gamma 0.2; [t,y] ode45(@(t, y) mass_spring_ext(t,y,gamma), [0 100], [1; 0]); plot(t,y(:,1), '+'); hold on; 6 7 8 9 10 11 12 13 14 [t,y] => 15 16 gamma 0.42; ode45(@(t,y) mass_spring_ext(t,y,gamma), [0 100], [1; 0]); plot(t,y(:,1),'-'); hold on; gamma = 0.6; ode45 (@(t,y) mass_spring_ext(t,y, t,y,gamma), [0 100],[1; 0]); plot(t,y(:,1),'-o'); hold on; ode45 (@(t, y) mass_spring_ext(t,y,gamma), [0 100], [1; 0]); 17 18 [t,y] = 19 20 21 gamma 0.8; 22 [t,y] 23 24 25 26 27 28 29 plot(t,y(:,1), ); hold off; xlabel( Time t'); ylabel('Solution y'); legend (gamma-0.2', 'gamma-0.42', 'gamma-0.6', 'gamma-0.8'); 30 Ε 31 32 33 34 35 36 37 38 %%%% %%% plotting the amplitude of the steady-state solution (A(gamma)-FO*M(gamma)) vs gamma figure; = = m= 1; k 1/5; b 1/5; F0 = 1; gama = 0.2:0.01:0.8; M_gama FO./sqrt((k-m*gama. ^2).^2+b^2*gama. ^2); plot (gama, M_gama); xlabel('gamma'); ylabel('A(gamma)'); 1. A mass-spring motion is governed by the ordinary differential equation d²x dx m. +b dt² dt +k(t)x = F(t), where m is the mass, b is the damping constant, k is the spring constant, and F(t) is the external force. We consider the initial conditions x(0): = 1 and x'(0) = 0. Assume the following numerical values for this part of the project: m = 1, k = 1/4, b=1/5, and F(t) = sin yt. (a) Read section 4.10. Explain what is the resonance frequency, and then compute the resonance frequency for this mass-spring system. (b) The ODE45-solver can be used to obtain the solution curves in MATLAB. Use the script Project2_Q1.m to plot the solutions and estimate the amplitude A of the steady response for Y === 0.25, 0.45, 0.65, and 0.85. (c) The script also provide you with the graph of A versus y. For what frequency y is the amplitude the greatest? Is it equal to that you obtained in (a)?
%%% plotting the solution y for each gamma figure; = gamma 0.2; [t,y] ode45(@(t, y) mass_spring_ext(t,y,gamma), [0 100], [1; 0]); plot(t,y(:,1), '+'); hold on; 6 7 8 9 10 11 12 13 14 [t,y] => 15 16 gamma 0.42; ode45(@(t,y) mass_spring_ext(t,y,gamma), [0 100], [1; 0]); plot(t,y(:,1),'-'); hold on; gamma = 0.6; ode45 (@(t,y) mass_spring_ext(t,y, t,y,gamma), [0 100],[1; 0]); plot(t,y(:,1),'-o'); hold on; ode45 (@(t, y) mass_spring_ext(t,y,gamma), [0 100], [1; 0]); 17 18 [t,y] = 19 20 21 gamma 0.8; 22 [t,y] 23 24 25 26 27 28 29 plot(t,y(:,1), ); hold off; xlabel( Time t'); ylabel('Solution y'); legend (gamma-0.2', 'gamma-0.42', 'gamma-0.6', 'gamma-0.8'); 30 Ε 31 32 33 34 35 36 37 38 %%%% %%% plotting the amplitude of the steady-state solution (A(gamma)-FO*M(gamma)) vs gamma figure; = = m= 1; k 1/5; b 1/5; F0 = 1; gama = 0.2:0.01:0.8; M_gama FO./sqrt((k-m*gama. ^2).^2+b^2*gama. ^2); plot (gama, M_gama); xlabel('gamma'); ylabel('A(gamma)'); 1. A mass-spring motion is governed by the ordinary differential equation d²x dx m. +b dt² dt +k(t)x = F(t), where m is the mass, b is the damping constant, k is the spring constant, and F(t) is the external force. We consider the initial conditions x(0): = 1 and x'(0) = 0. Assume the following numerical values for this part of the project: m = 1, k = 1/4, b=1/5, and F(t) = sin yt. (a) Read section 4.10. Explain what is the resonance frequency, and then compute the resonance frequency for this mass-spring system. (b) The ODE45-solver can be used to obtain the solution curves in MATLAB. Use the script Project2_Q1.m to plot the solutions and estimate the amplitude A of the steady response for Y === 0.25, 0.45, 0.65, and 0.85. (c) The script also provide you with the graph of A versus y. For what frequency y is the amplitude the greatest? Is it equal to that you obtained in (a)?
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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