The equation for the motion of red ball at heights and time t after release is s=-2.2t^(2) + 2.2t + 26.4 while the equation for the motion of blue ball is s=-4.9t^(2) + 19.6t + 58.8. If both balls are released together from the same distance, which ball strikes the ground first? Justify your answer
The equation for the motion of red ball at heights and time t after release is s=-2.2t^(2) + 2.2t + 26.4 while the equation for the motion of blue ball is s=-4.9t^(2) + 19.6t + 58.8. If both balls are released together from the same distance, which ball strikes the ground first? Justify your answer
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Transcribed Image Text:The equation for the motion of red
ball at height s and time t after
release is s=-2.2t^(2) + 2.2t + 26.4
while the equation for the motion of
blue ball is s=-4.9t^(2) + 19.6t + 58.8.
If both balls are released together
from the same distance, which ball
strikes the ground first? Justify your
answer
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