The equation for the liquid-gas line is: ln (P2/P1) = (−∆vapHm / R)∙ ( 1/T2 - 1/T1). At what temperature does H2O boil given that the triple point is at T = 273.16 K and P = 611.73 Pa and ∆vapHm is 40.65 kJ/mol? Hint: What do you use for P2 to calculate T2? The equation for the solid-gas line is: ln (P2/P1) = (−∆subHm/ R)∙ ( 1/T2− 1/T1). At what temperature does CO2 sublime at given that the triple point is at 216.6 K and 518.5 kPa and ∆subHm is 25.2 kJ/mol? Hint: What do you use for P2 to calculate T2 ?
The equation for the liquid-gas line is: ln (P2/P1) = (−∆vapHm / R)∙ ( 1/T2 - 1/T1). At what temperature does H2O boil given that the triple point is at T = 273.16 K and P = 611.73 Pa and ∆vapHm is 40.65 kJ/mol? Hint: What do you use for P2 to calculate T2? The equation for the solid-gas line is: ln (P2/P1) = (−∆subHm/ R)∙ ( 1/T2− 1/T1). At what temperature does CO2 sublime at given that the triple point is at 216.6 K and 518.5 kPa and ∆subHm is 25.2 kJ/mol? Hint: What do you use for P2 to calculate T2 ?
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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The equation for the liquid-gas line is: ln (P2/P1) = (−∆vapHm / R)∙ ( 1/T2 - 1/T1). At what temperature does H2O boil given that the triple point is at T = 273.16 K and P = 611.73 Pa and ∆vapHm is 40.65 kJ/mol? Hint: What do you use for P2 to calculate T2?
The equation for the solid-gas line is: ln (P2/P1) = (−∆subHm/ R)∙ ( 1/T2− 1/T1). At what temperature does CO2 sublime at given that the triple point is at 216.6 K and 518.5 kPa and ∆subHm is 25.2 kJ/mol? Hint: What do you use for P2 to calculate T2 ?
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