Calculate the enthalpy and entropy values of the saturated isobutane vapor at 340 K using the information in the table below. The vapor pressure at 340K is 8 bar.300 K and 1 bar (ideal gas reference state ) H0ig = 18,115 J/mol, S0ig= 295.976 J/molK = 1.7765 + 33.037 x 10-3 T(T: Kelvin)RР (bar)T=340 KT=350 KT=360 KT=370 KT=380 K0.100.997000.997190.997370.997530.997670.500.987450.988300.989070.989770.9904020.958950.962060.964830.967300.9695340.924220.930690.936350.941320.9457460.887420.898160.907340.915290.9222380.845750.862180.875860.887450.89743100.796590.821170.840770.856950.87061120.773100.801030.823150.84134140.755060.785310.8092315.410.71727

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Answered: Calculate the enthalpy and entropy…

Introduction to Chemical Engineering Thermodynamics

8th Edition

ISBN:9781259696527

Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart

Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart

Chapter1: Introduction

Section: Chapter Questions

Problem 1.1P

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Calculate the enthalpy and entropy values of the saturated isobutane vapor at 340 K using the information in the table below. The vapor pressure at 340K is 8 bar.

300 K and 1 bar (ideal gas reference state ) H₀^ig = 18,115 J/mol, S₀^ig= 295.976 J/molK

= 1.7765 + 33.037 x 10-3 T
(T: Kelvin)
R
Р (bar)
T=340 K
T=350 K
T=360 K
T=370 K
T=380 K
0.10
0.99700
0.99719
0.99737
0.99753
0.99767
0.50
0.98745
0.98830
0.98907
0.98977
0.99040
2
0.95895
0.96206
0.96483
0.96730
0.96953
4
0.92422
0.93069
0.93635
0.94132
0.94574
6
0.88742
0.89816
0.90734
0.91529
0.92223
8
0.84575
0.86218
0.87586
0.88745
0.89743
10
0.79659
0.82117
0.84077
0.85695
0.87061
12
0.77310
0.80103
0.82315
0.84134
14
0.75506
0.78531
0.80923
15.41
0.71727

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