The energy stored in the electric field produced by a metal sphere is 4.5 J. If the sphere contains 4 µC charge, its 1 = 9×10°N – m² / C²] 4 TEO radius will be :[Take : %3D | (a) 20mm (b) 32mm (c) 28mm (d) 16mm
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![energy stored in the electric field produced by a metal
sphere is 4.5 J. If the sphere contains 4 µC charge, its
The
1
- = 9×10°N – m² / C²]
Απερ
radius will be :[Take :
(a) 20mm
(b) 32mm (c) 28mm
(d) 16mm](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1343b8e3-603b-47b2-a187-92dd680519d9%2Fb9a46b85-ca3c-4739-af43-ad79f3c85321%2F0l3xdm_processed.jpeg&w=3840&q=75)
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- An electric field is given as 10e' (sin2za_ + xsin2za + 2xcos2za )V/m E =- y Find E at P(5, 0,2).A thick insulating spherical shell of inner radius a = 3, 13R and outer radius b = a uniform charge density p. = a b 10, 73R has What is the magnitude of the electric field at r = 14, 82R? Express your answer using two PR decimal places in units of1.6. A uniformly charged insulating rod is bent into the shape of a semicirele of radius R = 5 cm. If the rod has a total charge of Q = 3.10°C, find the magnitude and direction of the electric field at 0, the center of the circle. (Answer: E = 6,84.10ʻV/m)
- Calculate the net charge on a substance consisting of a combination of 7.3 * 10^13 protons and 7.6 * 10^13 electrons. The elemental charge is 1.6*10^-19 C.Determine the volume charge density, in pC/m3, at (3, -8, -2) if the electric field present in the region is E = sin (3 x + 2 y + 3 z) V/m. All coordinates are measured in meters.Suppose a capacitor consists of two coaxial thin cylindrical conductors. The inner cylinder of radius ra has a charge of +Q, while the outer cylinder of radius rp has charge -Q. The electric field E at a radial distance r from the central axis is given by the function: E = aer/ao + B/r + bo %3D where alpha (a), beta (B), ao and bo are constants. Find an expression for its capacitance. First, let us derive the potential difference Vab between the two conductors. The potential difference is related to the electric field by: Vab = | S"Edr= - [ *Edr Calculating the antiderivative or indefinite integral, Vab = (-aage-r/ao + B + bo By definition, the capacitance C is related to the charge and potential difference by: C = Evaluating with the upper and lower limits of integration for Vab, then simplifying: C = Q/( (e-rb/ao - eralao) + B In( ) + bo ( ))
- eff 11 Ker + R3 R ko 4R P H2HJR What is V (4B)-V (0) ? insulating sphere is evenly distribuated throughout the volume).00 44E0 Give an expression for the electric field strength E at a point in terms of the charge q and distance r from the charge to that point. Use k for k = 47). Flag question (i.e. Use the following notation (without the quotes): "/" for division, "*" for multiplication, "+" an "-" as usual. For powers used "^2", while for square root use "sqrt". To indicate that square root applies to the whole expression use brackets - for example, for √AB use sqrt(A*B). For Greek letters such as π, a etc. use pi, alpha. For example to get 1 AVAB use 1/pi* A^2/B*sqrt(AB). Please use the exact variables given in the conditions of the problem: e.gif L is given, then do not use 1. Please use "Display response" button to check the you entered correct expression, before submitting your answer. л вTwo parallel conducting plates, each of cross-sectional area 400 cm2, are 2.0 cm apart and uncharged. If 1.01012 electrons are transferred from one plate to the other, what are (a) the charge density on each plate? (b) The electric field between the plates?
- Electric charge is distributed over the triangular region D shown below so that the charge density at (r, y) is o(x, y) = 3ry, measured in coulumbs per square meter (C/m2). Find the total charge on 4 3 21 2. 4 coulumbsSuppose a capacitor consists of two coaxial thin cylindrical conductors. The inner cylinder of radius ra has a charge of +Q, while the outer cylinder of radius rp has charge -Q. The electric field E at a radial distance r from the central axis is given by the function: E = ae-T/ao + B/r + bo where alpha (a), beta (8), ao and bo are constants. Find an expression for its capacitance. First, let us derive the potential difference Vah between the two conductors. The potential difference is related to the electric field by: Vab = Edr = - Edr Calculating the antiderivative or indefinite integral, Vab = (-aage-r/a0 + B + bo By definition, the capacitance Cis related to the charge and potential difference by: C = Evaluating with the upper and lower limits of integration for Vab, then simplifying: C= Q/( (e-rb/ao - eTalao) + B In( ) + bo ( ))Question 1 6 p A spherical conductor has a radius of 8 mm and a charge of 20µC. Calculate the electric field at r = 6mm. O V/m 5 GV/m 2.815 GV/m 9 GV/m
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