The energy of the first excited quantum state of a particle in the two-dimensional potential 1 V(x,y) =mo (x² +4y²) is: (a) 2ho (b) 3ħo (c) ho (d) - ħo
The energy of the first excited quantum state of a particle in the two-dimensional potential 1 V(x,y) =mo (x² +4y²) is: (a) 2ho (b) 3ħo (c) ho (d) - ħo
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![The energy of the first excited quantum state of a particle in the two-dimensional potential
V(1,y)=mo" (2* + 4y") is
(c) 2
(d) ho
(a) 2ho
(b) 3ħo](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F044c2fef-7f7f-44ad-a61d-5e9581d5c5e9%2Fdc69138d-d575-46af-acf3-459dcb96060d%2Fgdryfv7d_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The energy of the first excited quantum state of a particle in the two-dimensional potential
V(1,y)=mo" (2* + 4y") is
(c) 2
(d) ho
(a) 2ho
(b) 3ħo
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