The emf devices and lightbulbs in the figure below are identical. The terminal potential of the emf device is 8.50 V. The current through bulb A is 5.00 mA. A B (a) Find the current through bulb B. 5.00 mA (b) What is the current through bulb C? E Ⓡ с
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- 7.10 N, R2 = = 7.00 N, and R, = 3.70 N. The two batteries each have a voltage of 5.00 V. %3D %3D The resistors in the circuit below have the following values: R, R2 R1 R3 E2 (a) Find the current in through R2. A (b) How much power do the batteries deliver to R,? W wwει R1 a R1 w R2 R1 www R1 As shown in the figure, the resistances are R1 = 3.0 2 and R2 = 6.0 2, and the ideal batteries have emfs E₁ = 5.0 V, and E2 = E3 = 10.0 V. What is the size and direction of the current in battery 1 (ta positive current as that flowing through the battery from - to +)? Submit Answer Tries 0/10 What is the size and direction of the current in battery 2 (take positive current as that flowing through the battery from to +)? Submit Answer Tries 0/10 What is the size and direction of the current in battery 3 (take positive current as that flowing through the battery from - to +)? Submit Answer Tries 0/10 What is the potential difference Va - Vb? Submit Answer Tries 0/10Two lightbulbs both operate on separate 120 V sources. One has a power of 40 W and the other is 80 W. Which of the following is true? o a. they have the same current flowing o b. the 80 w bulb has more current flowing O c. the 40 W bulb has a lower resistance o d. they have the same resistance
- You charge an initially uncharged 72.9 mF capacitor through a 27.9 2 resistor by means of a 9.00 V battery having negligible internal resistance. Find the time constant t of the circuit. T = S What is the charge Q on the capacitor 1.71 time constants after the circuit is closed? Q = C What is the charge Qo after a long amount of time has passed? Cla. This resistor has a resistance of 48002, and 32mA of current flows to the left into it. The right end of the resistor is at a potential of VR= 12.5V. What is the potential difference AV across the resistor? - VL? resistor 1b. What is the potential VL of the left end of the resistor? 1c. What is the power output by the resistor? R = 4800 1d. What is the current that flows out of the resistor? I = 32mA o at io. - VR=12.5V or gads di ei tedw $70 a vrutsd ads to bas ovisyon siis liszugA capacitor with a capacitance of 3.5 μF is initially uncharged. It is connected in series with a switch of negligible resistance, a resistor with a resistance of 19 kΩ, and a battery that has a potential difference of 170 V. What is the charge Q, in microcoulombs, on the capacitor when the current in the resistor equals one half its maximum value.
- none of the preceding DETAILS SHIPPS15 8.2.E.020. Two resistors with values of 29 0 and 45 0, respectively, are connected in parallel and hooked to a 18 V batte (a) What would be the current in the circuit? A (b) What would be the power expended in the circuit? W DETAILS SHIPPS15 8.2.E.018. A 13.0 W LED light bulb is turned on. It has an operating voltage of 120 V. (a) How much current (in A) flows through the bulh?Two cylindrical resistors are made from the same material and are equal in diameter. The first resistor has length L, and the second resistor has length 2L. If the same current flows through both, compare the voltage across the two resistors: V1 > V2 V1 = V2 V1 < V2 none of the above26.11 In Fig. E26.11, R₁ = 3.00, R₂ = 6.00 , and R3 = 5.00 2. The battery has negligible internal resistance. The current 1₂ through R₂ is 4.00 A. (a) What are the currents I₁ and 13? (b) What is the emf of the battery? Figure E26.11 R₁ R₂ www R3
- The emf devices and lightbulbs in the figure below are identical. The terminal potential of the emf device is 4.00 V. The current through bulb A is 5.60 mA. A В C (a).Find the current through bulb B. MA Enter a number. (b) What is the current through bulb C? mAThe brightness of a lightbulb is dependent on the current that goes through the lightbulb (in reality on the power, which is I^2/R). In Europe, the voltage used is 220 Volts, as opposed to the 120 Volts used in the USA. Will a lighbulb that is made for European voltage work well or poorly in the USA? It will work poorly in the USA. Since I=V/R, if V decreases, so does I, and so does the brightness. It will work more efficiently in the USA. Since I=V/R, if V decreases, I increases, and the brightness increases. It will work better in the USA because the resistance of the wires is smaller. Whether it works better or worse depends on how modern the wiring system is, regardless of the voltage, V.