The elevator starts from rest at the first floor and accelerates at 2.46 ft/s^2 for 5 seconds and continues for 12 seconds at constant velocity then stops at constant acceleration in 3 seconds. If the building have 20 floors and each floor is 12.3 ft apart, at what floor did the elevator stop? (Answer should be in fps)
The elevator starts from rest at the first floor and accelerates at 2.46 ft/s^2 for 5 seconds and continues for 12 seconds at constant velocity then stops at constant acceleration in 3 seconds. If the building have 20 floors and each floor is 12.3 ft apart, at what floor did the elevator stop? (Answer should be in fps)
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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The elevator starts from rest at the first floor and accelerates at 2.46 ft/s^2 for 5 seconds and continues for 12 seconds at constant velocity then stops at constant acceleration in 3 seconds. If the building have 20 floors and each floor is 12.3 ft apart, at what floor did the elevator stop? (Answer should be in fps)
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Step 1 :Introduction
VIEWStep 2 :Explanation
VIEWStep 3 :Calculation of the vertical distance travelled in first case
VIEWStep 4 :Calculation of the final velocity of the elevator in first case
VIEWStep 5 :Calculation of the vertical distance travelled in second case
VIEWStep 6 :Calculation of the acceleration required to stop the elevator
VIEWStep 7 :Calculation of the vertical distance travelled in third case
VIEWStep 8 :Calculation of the total vertical distance travelled
VIEWStep 9 :Calculation of the number of floor
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