(a) What is the speed of the ball at the bottom of the first plane (in m/s)? (Round your answer to at least two decimal places.) m/s (b) How long does it take to roll down the first plane (in s)? (c) What is the magnitude of the acceleration along the second plane (in m/s2)? m/s²

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Chapter1: Units, Trigonometry. And Vectors
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A volleyball starts from rest and accelerates with an acceleration of 0.405 m/s2 while moving down a 8.75 m long inclined plane. When it reaches the bottom, the ball rolls up another plane, where, after moving 15.00 m, it comes to rest.

 

 

(a) What is the speed of the ball at the bottom of the first plane (in m/s)? (Round your answer to at least two decimal places.)
m/s
(b) How long does it take to roll down the first plane (in s)?
(c) What is the magnitude of the acceleration along the second plane (in m/s?)?
m/s2
(d) What is the ball's speed 8.10 m along the second plane (in m/s)?
m/s
(e) What If? You change the angles of the two inclines in such a manner that the new acceleration down the first incline is a now dewn = 2a initial dewn and up the second incline is
ax new up
x initial up, What is the ball's speed 8.10 m up the second plane (in m/s)?
m/s
Transcribed Image Text:(a) What is the speed of the ball at the bottom of the first plane (in m/s)? (Round your answer to at least two decimal places.) m/s (b) How long does it take to roll down the first plane (in s)? (c) What is the magnitude of the acceleration along the second plane (in m/s?)? m/s2 (d) What is the ball's speed 8.10 m along the second plane (in m/s)? m/s (e) What If? You change the angles of the two inclines in such a manner that the new acceleration down the first incline is a now dewn = 2a initial dewn and up the second incline is ax new up x initial up, What is the ball's speed 8.10 m up the second plane (in m/s)? m/s
Expert Solution
Step 1

Given data:

The initial velocity of the volleyball is,

u = 0 m/s

 Acceleration of the volleyball is,

a = 0.405 m/s2

A volleyball move down a distance of 

d1 = 8.75 m inclined plane

After reaching the bottom volleyball, again rolls up another plane, where, after moving 15.00 m

d2 = 15 m

Formula used:

According to the kinematical equation of motion,

v2 = u2 + 2adv = u + at

Where,

v- Final velocity

u- Initial velocity

a- Acceleration

d- Displacement

 

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