The displacement vectors A and B shown in the figure below both have magnitudes of 4.45 m. The direction of vector A is0 = 43.0⁰.0(a) Find A + B graphically.magnitude 8.16direction66.5(b) Find A - B graphically.magnitude 3.55direction-23.5= 2(c) Find B- A graphically.magnitude 3.55direction156.5direction✓ m✓Need Help?Read It↑• counterclockwise from the +x axis✔m✓ ° counterclockwise from the +x axis(d) Find A - 2B graphically.3.55Xmagnitude.Your response differs from the correct answer by more than 10%. Double check your calculations. m156.5 Xcounterclockwise from the +x axis✓ m• counterclockwise from the +x axisMaster It 7:29SearchWe investigated a jet landing on an aircraft carrier. In a later maneuver, the jet comes in for a landing on solid groundwith a speed of 92 m/s, and its acceleration can have a maximum magnitude of 8.75 m/s² as it comes to rest.(a) From the instant the jet touches the runway, what is the minimum time interval needed before it can cometo rest?(b) Can this jet land on a small tropical island airport where the runway is 0.800 km long?(c) Explain your answer.Step 1We know the initial speed of the jet when it touches the runway, and we know that its final speed is zero. We also knowthe maximum magnitude that its acceleration can have when it comes to rest. We need to find the stopping distance forthe jet and we need to compare this stopping distance to the length of the runway on the island airport.10.47Step 2We use the maximum acceleration and the initial and final velocities to determine the minimum stopping time. We knowthe initial and final velocities of the jet and we know the maximum value of its acceleration. We need to find thedisplacement x,- x,- Ax that corresponds to these values. We are given that the length of the runway is 0.800 km. Wecalculate the minimum stopping distance based on the initial and final velocities and the maximum acceleration of thejet as it comes to rest on the runway. Is the runway long enough for the jet to land safely?Step 3(a) We use the equation for velocity with constant acceleration.V=V+atNow, solve for t in the above equation. Substitute the values we know for final velocity v initial velocity Vandacceleration a,a.-10.51✔(0Solve for Ax.-8.75 ✓0 m/s0 m/s 92✔92✔✔ 92 m/s-8.75 m/s2Step 4(b) We have the following equation in terms of displacement, velocity, and acceleration.v²=v²+2a₂(x-x) = v₁² + 2a, AxNow, substitute the values we know into this equation.✔m/s)²-(9210.5 s✔m/s)2 + 2( -8.75и✔m/s2)AxAx- 0.800xYour response differs from the correct answer by more than 10%. Double check your calculations. kmWe have found that the stopping distance Ax is less than0.800 km.EP

Answered: Image /qna-images/answer/6853782e-8518-4661-932c-7e2e0f16252c.jpg

(a) Find A + B graphically. magnitude direction 8.16 66.5 (b) Find A - B graphically. magnitude direction 3.55 -23.5 (c) Find B - A graphically. magnitude direction 3.55 156.5 m count m count m count (d) Find A - 2B graphically. 3.55 X magnitude Your response differs from 156.5 x count direction

(a) Find A + B graphically. magnitude direction 8.16 66.5 (b) Find A - B graphically. magnitude direction 3.55 -23.5 (c) Find B - A graphically. magnitude direction 3.55 156.5 m count m count m count (d) Find A - 2B graphically. 3.55 X magnitude Your response differs from 156.5 x count direction

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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