The electric field of an EM wave in vacuum is given by Er = 30 cos (27 × 10°t + 3); Ey = 0; Ez = 0; where E is in volts/meter, t in seconds, and x in meters. Determine the frequency f, the wavelength A, the direction of propagation of the wave, the direction and amplitude of the magnetic field.
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- The average intensity of an EM wave is 4.50×10^7 W/m^2. What is the peak amplitude of the electric field of this wave? What is the peak amplitude of the magnetic field of this wave?The electric field of an electromagnetic wave in a vacuum is Ey =( 23.0 V/m)cos((V/m)cos(( 9.78 ×108)x−ωt), where x is in mm and t is in s. What s the wave's wavelength? Express your answer with the appropriate units. What is the wave's frequency? Express your answer with the appropriate units. What is the wave's magnetic field amplitude? Express your answer with the appropriate units.Please keep all decimals