A planar electromagnetic wave is propagating in the -x direction. At a certain point \( P \) and at a given instant, the electric field of the wave is given by \( \mathbf{E} = (1.27 \, \text{V/m}) \, \hat{\mathbf{j}} \). What is the magnitude and direction of the magnetic field vector of the wave (in nT) at the point \( P \) at that instant? Denote the +z direction as positive, and the -z direction as negative. (Use \( c = 2.9979 \times 10^8 \, \text{m/s} \))________ nT[Input Box]

Answered: Image /qna-images/answer/c26b278e-59f1-4d3c-b3dc-3070e617945a.jpgThe magnitude of magnetic field is 4.24 nT and directed along -z direction.

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Advanced Physics

A planar electromagnetic wave is propagating in the -x direction. At a certain point P and at a given instant, the electric field of the wave is given by E = (1.27 V/m)ĵ. What is the magnitude and direction of the magnetic field vector of the wave (in nT) at the point P at that instant? Denote the +z direction as positive, and the -z direction as negative. (Use c = 2.9979 × 108 m/s) nT

A planar electromagnetic wave is propagating in the -x direction. At a certain point P and at a given instant, the electric field of the wave is given by E = (1.27 V/m)ĵ. What is the magnitude and direction of the magnetic field vector of the wave (in nT) at the point P at that instant? Denote the +z direction as positive, and the -z direction as negative. (Use c = 2.9979 × 108 m/s) nT