The electric field at a point on the perpendicular bisector of a dipole is directed ______ a) Along the dipole moment b) Perpendicular to the dipole moment c) Opposite to the dipole moment d) 45 degree to the dipole moment
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The electric field at a point on the perpendicular bisector of a dipole is directed ______
a) Along the dipole moment
b) Perpendicular to the dipole moment
c) Opposite to the dipole moment
d) 45 degree to the dipole moment

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- 1) An initially non-charged gold leaf inside an electroscope has a total dimension of 2 [cm] x 4[cm]. It is folded in half to have two equal squares of 2 [cm] x 2 [cm] on either side.1a) A charged probe of +5*10^(-6) [C] is brought near the tip of the electroscope but does nottouch. What effect do you predict will happen to the gold leaves and why?1b) The same charged probe now makes contact to the electroscope and it's net charge isreduced to +2.5*10^(-6) [C] and the electroscope is removed. Explain what had happened andwhat is the surface charge density of each of the squares of the gold leaf?1c) If the gold leaf squares are separated by an angle of 90 degrees, what is the magnitude ofthe electric force per area between the centers of the squares?Elcetvic Field Produced by The a tmos Pher iF The is loo Ne inhat the Poten tral diffesence pa baltery terminali E Zom Is 18V with + rerminal having Potential. IF ! how much Potential Energy dors il lese is the Potential al Elovation Som The heigher Ar charge tr avels From n-8(a) What is the dipole moment of the configuration shown above? If Q = 4.0 μC , (b) what is the torque on this dipole with an electric field of 4.0 x 10^5 N/C i? (c)What is the torque on this dipole with an electric field of −4.0 x 10^5 N/C i? (d) What is the torque on this dipole with an electric field of ±4.0 x 10^5 N/C j? a=4.0
- Calculate the magnitude and direction of the Coulomb force on each of the three charges shown in the figure below. 6.00 μC 1.50 μC -2.00 μC 6.00 μC charge 6.00 μC charge 3.00 cm -2.00 μC charge -2.00 μC charge 1.50 μC charge magnitude 1.50 μC charge direction magnitude direction ---Select--- -2.00 cm magnitude direction ---Select--- ---Select--- N N N VDipole consisting of two equal but opposite point charges separated by a distance "2L". The magnitude either dipole charge is , "qd". A vector quantity called the Electric Dipole Moment Vector ,p ,is defined to have a magnitude p = (qd)(d) (d= separation distance of the dipole charges) and a unit vector direction pointing from negative to positve charge Find the dipole moment vector “p”In this problem we explore dipoles as sources of fields and their interactions with other charges An induced dipole is a dipole (separated, opposite charges) whose charge separation and dipole moment are caused by the presence of an external electric field, often due to some other source charge. Often, the induced dipole moment is proportional to that electric field at the location of the dipole. For example, when a charged piece of tape is near your finger, the charges inside the neutral atoms in your finger move in response to the tape's field at the location of the finger, and each atom in the finger becomes a dipole. The closer the tape is to the finger, the stronger the tape's field, the more the charges move and the larger the dipole moments of the atoms in the finger. Mathematically, we can write this as p = aE, where p is the dipole moment, E is the strength of the electric field at the location of the dipole, and a is a constant that depends on the type of atom and gives the…
- Item 6 For the steps and strategies involved in solving a similar problem, you may view the following Example 19-6 video: Part A r = Submit Request Answer ? REASONING AND STRATEGY The net force on q, is the vector sum of the forces due to q, and q₂ = ₁ + ₁₂ We can find the magnitudes of the forces from Coulomb's law: 1911 191 [૧] [૩] m 0 F33- At what separation is the electrostatic force between a +13.0 μC point charge and a +28.2 μC point charge equal in magnitude to 1.85 N ? Express your answer in meters. —| ΑΣΦ F3₂-k 0.55 m Fyz 532 19one chargel 19another chargel (between charges) k-8.99 x 10 N-m²/C² 92 1.00 m101) An initially non-charged gold leaf inside an electroscope has a total dimension of 2 [cm] x 4[cm]. It is folded in half to have two equal squares of 2 [cm] x 2 [cm] on either side.1a) A charged probe of +5*10^(-6) [C] is brought near the tip of the electroscope but does nottouch. What effect do you predict will happen to the gold leaves and why? 1b) The same charged probe now makes contact to the electroscope and it's net charge isreduced to +2.5*10^(-6) [C] and the electroscope is removed. Explain what had happened andwhat is the surface charge density of each of the squares of the gold leaf? 1c) If the gold leaf squares are separated by an angle of 90 degrees, what is the magnitude ofthe electric force per area between the centers of the squares? got part B I got -6.25*10^-3 and for part C I got -281.25 N/m^2 is this correct?