The electric field along the axis of a ring-shaped charge of total charge q distributed uniformly is given by E = where R is the radius of the ring and z is the distance from the center of the ring. The electric field at the center of the ring is zero and at great distances from the ring approaches zero. At a certain distance along the z-axis the electric field strength is maximum. What is the electric field strength at this point? 9 3√√3лE R² 9 2√√3лER² 9 5√√3 TER² q 6√√3лE R² qz 3/2 4лεo (z² + R²)³ 9 4√√3лER² 4₁
The electric field along the axis of a ring-shaped charge of total charge q distributed uniformly is given by E = where R is the radius of the ring and z is the distance from the center of the ring. The electric field at the center of the ring is zero and at great distances from the ring approaches zero. At a certain distance along the z-axis the electric field strength is maximum. What is the electric field strength at this point? 9 3√√3лE R² 9 2√√3лER² 9 5√√3 TER² q 6√√3лE R² qz 3/2 4лεo (z² + R²)³ 9 4√√3лER² 4₁
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![### Electric Field on the Axis of a Ring-Shaped Charge
The electric field along the axis of a ring-shaped charge of total charge \( q \) distributed uniformly is given by:
\[ E = \frac{qz}{4 \pi \epsilon_0 \left( z^2 + R^2 \right)^{3/2}} \]
where \( R \) is the radius of the ring and \( z \) is the distance from the center of the ring. The electric field at the center of the ring is zero, and at great distances from the ring, it approaches zero. At a certain distance along the z-axis, the electric field strength is maximum. What is the electric field strength at this point?
### Answer Choices
1. \( \frac{q}{3\sqrt{3} \pi \epsilon_0 R^2} \)
2. \( \frac{q}{2\sqrt{3} \pi \epsilon_0 R^2} \)
3. \( \frac{q}{5\sqrt{3} \pi \epsilon_0 R^2} \)
4. \( \frac{q}{6\sqrt{3} \pi \epsilon_0 R^2} \)
5. \( \frac{q}{4\sqrt{3} \pi \epsilon_0 R^2} \)
These are the potential answers to find the electric field strength at the point where the electric field is maximum along the z-axis.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F67028db1-3c15-42d7-aa43-8659f6c3f0f2%2Fcf464811-68d4-46d1-9a9c-65cb785c973f%2Fznkc0bd_processed.png&w=3840&q=75)
Transcribed Image Text:### Electric Field on the Axis of a Ring-Shaped Charge
The electric field along the axis of a ring-shaped charge of total charge \( q \) distributed uniformly is given by:
\[ E = \frac{qz}{4 \pi \epsilon_0 \left( z^2 + R^2 \right)^{3/2}} \]
where \( R \) is the radius of the ring and \( z \) is the distance from the center of the ring. The electric field at the center of the ring is zero, and at great distances from the ring, it approaches zero. At a certain distance along the z-axis, the electric field strength is maximum. What is the electric field strength at this point?
### Answer Choices
1. \( \frac{q}{3\sqrt{3} \pi \epsilon_0 R^2} \)
2. \( \frac{q}{2\sqrt{3} \pi \epsilon_0 R^2} \)
3. \( \frac{q}{5\sqrt{3} \pi \epsilon_0 R^2} \)
4. \( \frac{q}{6\sqrt{3} \pi \epsilon_0 R^2} \)
5. \( \frac{q}{4\sqrt{3} \pi \epsilon_0 R^2} \)
These are the potential answers to find the electric field strength at the point where the electric field is maximum along the z-axis.
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