The electric field along the axis of a ring-shaped charge of total charge q distributed uniformly is given by E = where R is the radius of the ring and z is the distance from the center of the ring. The electric field at the center of the ring is zero and at great distances from the ring approaches zero. At a certain distance along the z-axis the electric field strength is maximum. What is the electric field strength at this point? 9 3√√3лE R² 9 2√√3лER² 9 5√√3 TER² q 6√√3лE R² qz 3/2 4лεo (z² + R²)³ 9 4√√3лER² 4₁

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### Electric Field on the Axis of a Ring-Shaped Charge

The electric field along the axis of a ring-shaped charge of total charge \( q \) distributed uniformly is given by:

\[ E = \frac{qz}{4 \pi \epsilon_0 \left( z^2 + R^2 \right)^{3/2}} \]

where \( R \) is the radius of the ring and \( z \) is the distance from the center of the ring. The electric field at the center of the ring is zero, and at great distances from the ring, it approaches zero. At a certain distance along the z-axis, the electric field strength is maximum. What is the electric field strength at this point?

### Answer Choices

1. \( \frac{q}{3\sqrt{3} \pi \epsilon_0 R^2} \)
2. \( \frac{q}{2\sqrt{3} \pi \epsilon_0 R^2} \)
3. \( \frac{q}{5\sqrt{3} \pi \epsilon_0 R^2} \)
4. \( \frac{q}{6\sqrt{3} \pi \epsilon_0 R^2} \)
5. \( \frac{q}{4\sqrt{3} \pi \epsilon_0 R^2} \)

These are the potential answers to find the electric field strength at the point where the electric field is maximum along the z-axis.
Transcribed Image Text:### Electric Field on the Axis of a Ring-Shaped Charge The electric field along the axis of a ring-shaped charge of total charge \( q \) distributed uniformly is given by: \[ E = \frac{qz}{4 \pi \epsilon_0 \left( z^2 + R^2 \right)^{3/2}} \] where \( R \) is the radius of the ring and \( z \) is the distance from the center of the ring. The electric field at the center of the ring is zero, and at great distances from the ring, it approaches zero. At a certain distance along the z-axis, the electric field strength is maximum. What is the electric field strength at this point? ### Answer Choices 1. \( \frac{q}{3\sqrt{3} \pi \epsilon_0 R^2} \) 2. \( \frac{q}{2\sqrt{3} \pi \epsilon_0 R^2} \) 3. \( \frac{q}{5\sqrt{3} \pi \epsilon_0 R^2} \) 4. \( \frac{q}{6\sqrt{3} \pi \epsilon_0 R^2} \) 5. \( \frac{q}{4\sqrt{3} \pi \epsilon_0 R^2} \) These are the potential answers to find the electric field strength at the point where the electric field is maximum along the z-axis.
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