The electric field 2.5 cm from an unknown charge has a strength of 428 N/C and points toward the charge. (a) What then is the electric potential at that distance, assuming there are no other point charges in the region? Vp = 1.2 x V (b) The electric field strength at a different point near another charge is 315 N/C.
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- A thin plastic rod of length d = 1.3 m lies along the x-axis with its midpoint at the origin. The rod carries a uniform charge density of λ = 9.5 nC/m. The point P is located along the y-axis at (0,y = 55 cm). Calculate the electric potential at P, in volts.The electric field 2.5 cm from an unknown charge has a strength of 428 N/C and points toward the charge. (a) What then is the electric potential at that distance, assuming there are no other point charges in the region? Vp = 428 x V (b) The electric field strength at a different point near another charge is 315 N/C. How far is this point from the charge if the electric potential there is -33 V? d = cmThe figure below shows two particles with 2.00-µC charges at x = -0.8 m and x = +0.8 m and a particle with charge q =1.2 × 10-18 C at the origin, (a) What is the net force exerted by the two 2.00-µC charges on the charge q? (b) What is the electric potential at the origin due to the two 2.00- HC particles? 2.00 μC 2.00 µC x = -0.800 m x= 0.800 m
- The electric potential in a region is given by the equation: V(x) = (2.00) x³ + (3.00) x. What is the electric field?A point charge of 25 µC is located at the the center of a thin spherical shell of 10 cm radius. This shell is uniformly charged with 11 µC. Find the electric field at r=5 cm and r=15. E1 = V/m, E2= V/m. What is the electric potential at these points? V1 = V, V2= V.The thin plastic rod of length L = 18.2 cm in the figure has a nonuniform linear charge density λ= cx, where c= 24.8 pC/m. (a) With V=0 at infinity, find the electric potential at point P₂ on the y axis at y D=4.90 cm. (b) Find the electric field component Ey at P₂. (a) Number i (b) Number i D d- Units V Units V/m
- Point charges qA = 6.6 nC is located at (0, 0) and qB = -3.0 nC is located at (5.00 m, 0). What is the electric potential at point P (2.00 m, 0), in Volts? 1.00 nC = 1.00 × 10-9 C. Use K = 9.00 × 109 N·m2/C2. Your answer needs to have 2 significant figures, including the negative sign in your answer if needed. Do not include the positive sign if the answer is positive. No unit is needed in your answer, it is already given in the question statement.A line of charge of linear density 2=4.5 nC/m lies on the x-axis and extends from x=-5.0 cm to x = 5.0 cm. Find, %3D A) The electric field on the x-axis at -5.5 cm. B) The electric potential at the point (-5.0, +5.0) cm on the x-y coordinate system.A spherical conductor with a radius of 73.5 cm has an electric field of magnitude 8.20 × 105 V/m just outside its surface. What is the electric potential just outside the surface, assuming the potential is zero far away from the conductor?