The eigenvalues of the coefficient matrix A are given. Find a general solution of the indicated system x' = Ax. 77 16 -32 -72 - 11 32 x; λ=-3, 5, 5 144 32 - 59 x(t) =

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Chapter1: Functions And Models
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**Problem Statement on Eigenvalues and Differential Equations**

The eigenvalues of the coefficient matrix \( A \) are given. Find a general solution of the indicated system \( \mathbf{x}' = A \mathbf{x} \).

Given the matrix \( A \) and the vector \( \mathbf{x} \):
\[
\mathbf{x}' = \begin{bmatrix}
77 & 16 & -32 \\
-72 & -11 & 32 \\
144 & 32 & -59 
\end{bmatrix} \mathbf{x}
\]
where the eigenvalues \( \lambda \) are \( -3, 5, 5 \).

**Solution Approach:**

To find the general solution of the system \( \mathbf{x}' = A \mathbf{x} \), where the matrix \( A \) has the eigenvalues \( -3, 5, 5 \), follow these steps:

1. **Eigenvector Calculation:** 
   - Determine the eigenvectors associated with each eigenvalue.
2. **General Solution Form:** 
   - The general solution to the system of differential equations is a linear combination of the solutions associated with each eigenvalue, where each solution is of the form \( \mathbf{x}(t) = \mathbf{v} e^{\lambda t} \). 
   - Since the eigenvalue \( 5 \) is repeated, you may also need to find a generalized eigenvector if \( \mathbf{v}_2 \) and \( \mathbf{v}_3 \) are not linearly independent.

Without further calculations, the general solution can be represented as:
\[
\mathbf{x}(t) = c_1 \mathbf{v}_1 e^{-3t} + c_2 \mathbf{v}_2 e^{5t} + c_3 \mathbf{v}_3 e^{5t}
\]
where \( \mathbf{v}_1 \), \( \mathbf{v}_2 \), and \( \mathbf{v}_3 \) are the eigenvectors associated with \( \lambda = -3 \) and \( \lambda = 5 \) respectively, and \( c_1 \), \( c_2 \), \( c_3 \) are constants determined by the initial conditions.

**Explanation of the Anticipated Diagrams or Graphs:**

- **Eigenvector Matrix:** A matrix diagram illustrating how to compute the eigenvectors from the eigen
Transcribed Image Text:**Problem Statement on Eigenvalues and Differential Equations** The eigenvalues of the coefficient matrix \( A \) are given. Find a general solution of the indicated system \( \mathbf{x}' = A \mathbf{x} \). Given the matrix \( A \) and the vector \( \mathbf{x} \): \[ \mathbf{x}' = \begin{bmatrix} 77 & 16 & -32 \\ -72 & -11 & 32 \\ 144 & 32 & -59 \end{bmatrix} \mathbf{x} \] where the eigenvalues \( \lambda \) are \( -3, 5, 5 \). **Solution Approach:** To find the general solution of the system \( \mathbf{x}' = A \mathbf{x} \), where the matrix \( A \) has the eigenvalues \( -3, 5, 5 \), follow these steps: 1. **Eigenvector Calculation:** - Determine the eigenvectors associated with each eigenvalue. 2. **General Solution Form:** - The general solution to the system of differential equations is a linear combination of the solutions associated with each eigenvalue, where each solution is of the form \( \mathbf{x}(t) = \mathbf{v} e^{\lambda t} \). - Since the eigenvalue \( 5 \) is repeated, you may also need to find a generalized eigenvector if \( \mathbf{v}_2 \) and \( \mathbf{v}_3 \) are not linearly independent. Without further calculations, the general solution can be represented as: \[ \mathbf{x}(t) = c_1 \mathbf{v}_1 e^{-3t} + c_2 \mathbf{v}_2 e^{5t} + c_3 \mathbf{v}_3 e^{5t} \] where \( \mathbf{v}_1 \), \( \mathbf{v}_2 \), and \( \mathbf{v}_3 \) are the eigenvectors associated with \( \lambda = -3 \) and \( \lambda = 5 \) respectively, and \( c_1 \), \( c_2 \), \( c_3 \) are constants determined by the initial conditions. **Explanation of the Anticipated Diagrams or Graphs:** - **Eigenvector Matrix:** A matrix diagram illustrating how to compute the eigenvectors from the eigen
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