The effectiveness of a new bug repellent is tested on 14 subjects for a 10 hour period. (Assume normally distributed population.) Based on the number and location of the bug bites, the percentage of surface area exposed protected from bites was calculated for each of the subjects. The results were as follows: I = 95, s == 15 The new repellent is considered effective if it provides a percent repellency of more than 91. Using a = 0.01, construct a hypothesis test with null hypothesis u = 91 and alternative hypothesis u > 91 to determine whether the mean repellency of the new bug repellent is greater than 91 by computing the following: (a) the degree of freedom (b) the test statistics (give to 3 decimal places)
The effectiveness of a new bug repellent is tested on 14 subjects for a 10 hour period. (Assume normally distributed population.) Based on the number and location of the bug bites, the percentage of surface area exposed protected from bites was calculated for each of the subjects. The results were as follows: I = 95, s == 15 The new repellent is considered effective if it provides a percent repellency of more than 91. Using a = 0.01, construct a hypothesis test with null hypothesis u = 91 and alternative hypothesis u > 91 to determine whether the mean repellency of the new bug repellent is greater than 91 by computing the following: (a) the degree of freedom (b) the test statistics (give to 3 decimal places)
MATLAB: An Introduction with Applications
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Author:Amos Gilat
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![**The Effectiveness of a New Bug Repellent**
The effectiveness of a new bug repellent is tested on 14 subjects over a 10-hour period. (Assume a normally distributed population.) Based on the number and location of the bug bites, the percentage of surface area exposed and protected from bites was calculated for each subject. The results were as follows:
- \(\bar{x} = 95\)
- \(s = 15\)
The new repellent is considered effective if it provides a percent repellency of more than 91. Using \(\alpha = 0.01\), construct a hypothesis test with the null hypothesis \(\mu = 91\) and alternative hypothesis \(\mu > 91\) to determine whether the mean repellency of the new bug repellent is greater than 91 by computing the following:
(a) The degree of freedom
(b) The test statistics (give to 3 decimal places)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa70a12d4-88d2-4e1f-8545-6de24188f77d%2F88bef3aa-6ff4-4b75-bc05-89f77f87ad44%2Fp6bg4kk_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**The Effectiveness of a New Bug Repellent**
The effectiveness of a new bug repellent is tested on 14 subjects over a 10-hour period. (Assume a normally distributed population.) Based on the number and location of the bug bites, the percentage of surface area exposed and protected from bites was calculated for each subject. The results were as follows:
- \(\bar{x} = 95\)
- \(s = 15\)
The new repellent is considered effective if it provides a percent repellency of more than 91. Using \(\alpha = 0.01\), construct a hypothesis test with the null hypothesis \(\mu = 91\) and alternative hypothesis \(\mu > 91\) to determine whether the mean repellency of the new bug repellent is greater than 91 by computing the following:
(a) The degree of freedom
(b) The test statistics (give to 3 decimal places)
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