The effectiveness of a blood-pressure drug is being investigated. Assume that the population standarddeviation is known to be 7.5 mmHg (millimeters of mercury). An experimenter finds that, on average,the reduction in systolic blood pressure is 20.4 mmHg for a sample of size 603.How much of mmHg will lower for a typical patient's systolic blood pressure after taking the drug?Estimate with 95% confidence.Preliminary: Is n > 30?O YesO NO4Confidence Interval: What are the two bounds for the 95% confidence interval to estimate thepopulation mean? Round your answers to one decimal place.εμε

The population standard deviation is 7.5 and the sample mean is 20.4.

Answered: The effectiveness of a blood-pressure…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Sulfur compounds cause "off‑odors" in wine, so winemakers want to know the odor threshold, the lowest concentration of a compound that the human nose can detect. The odor threshold for dimethyl sulfide (DMS) in trained wine tasters is about 25 micrograms per liter of wine (?g/L ). The untrained noses of consumers may be less sensitive, however. The DMS odor thresholds for 10 untrained students are given. 30 30 42 35 22 33 31 29 19 23 (a) Assume that the standard deviation of the odor threshold for untrained noses is known to be ?=7?g/Lσ To access the complete data set, click the link for your preferred software format: Do the three simple conditions hold in this case? Make a stemplot and use it to check the shape of the distribution. (b) STATE: What is the average (mean) DMS odor threshold, ?μ , for all untrained people? PLAN: Using the four‑step process, give a 95%95% confidence interval for the mean DMS odor threshold among all students. SOLVE: We have assumed that we…
Sulfur compounds cause "off‑odors" in wine, so winemakers want to know the odor threshold, the lowest concentration of a compound that the human nose can detect. The odor threshold for dimethyl sulfide (DMS) in trained wine tasters is about 25micrograms per liter of wine (?g/L ). The untrained noses of consumers may be less sensitive, however. The DMS odor thresholds for 10 untrained students are given. 30 30 42 35 22 33 31 29 19 23 SOLVE: We have assumed that we have a random sample and that the population from which we are sampling is Normal. Find ?¯ . (Enter your answer rounded to one decimal place.) ?¯= ?g/? Find the standard deviation, ??√, of the sampling distribution of ?¯. (Enter your answer rounded to four decimal places.) ??√=
High cholesterol is one of the major risk factors for heart disease. A total cholesterol reading above 190 mg/dL is considered high.A physician is concerned that a patient may be at risk for high cholesterol. In order to accurately measure the patient's average cholesterol level, the physician instructs the patient to come into the physician's office once a week for 12 weeks for a blood lipid screening. The results of the 12 measurements are listed below. 189 186 199 197 190 186 185 200 200 200 185 190 Use the critical value method to test the hypothesis that the patient's cholesterol level is greater than 190 mg/dL, using a significance level of 10%. Assume that the distribution of all cholesterol measurements from this patient is approximately normally distributed. Determine the critical value(s) for this hypothesis test. Round the solution(s) to four decimal places. If more than one critical value exists, enter the solutions using a comma-separated list.Determine the test…
A researcher wonders whether younger mothers have babies that are significantly heavier or lighter than the population average of μ 7.25 pounds. The researcher collects data from N = 35 babies who were born to mothers between the ages of 16 and 18. The average weight for these babies was M = 7.15 pounds (SD = .6 pounds).
Glaucoma is a leading cause of blindness in the United States, N. Ehlers measured the difference in corneal thickness (in microns) between the two eyes of eight patients. Each patient had one eye that had glaucoma and one eye that was normal. The difference was measured as the corneal thickness of normal eye – corneal thickness of eye with Glaucoma. Corneal thickness is important because it can mask an accurate reading of eye pressure. Use ? = .05 H0: μd=0 H1: μd≠0 T statistic: t = 1.053, P value = 0.327 Degrees of Freedom n-1 = 8-1= 7 critical value 2.3646 If t is less than 2.3646, or greater than 2.3646, reject the null hypothesis Level of significance: α=0.05 question: what a type 1 error and type 2 error would mean. Is it possible that we could have committed a type 2 error in conducting the test
Glaucoma is a leading cause of blindness in the United States, N. Ehlers measured the difference in corneal thickness (in microns) between the two eyes of eight patients. Each patient had one eye that had glaucoma and one eye that was normal. The difference was measured as the corneal thickness of normal eye – corneal thickness of eye with Glaucoma. Corneal thickness is important because it can mask an accurate reading of eye pressure. Use ? = .05. Q) If a participant has the same corneal thickness in their normal eye as the eye with Glaucoma, what would be the value for difference: measured as the corneal thickness of normal eye – corneal thickness of eye with Glaucoma.
Glaucoma is a leading cause of blindness in the United States, N. Ehlers measured the difference in corneal thickness (in microns) between the two eyes of eight patients. Each patient had one eye that had glaucoma and one eye that was normal. The difference was measured as the corneal thickness of normal eye – corneal thickness of eye with Glaucoma. Corneal thickness is important because it can mask an accurate reading of eye pressure. Use ? = .05. Q)Conduct a hypothesis test to determine if there is sufficient evidence to conclude that corneal thickness is different in normal eyes compared to eyes with glaucoma? Write up your results using the 8 steps.
Glaucoma is a leading cause of blindness in the United States, N. Ehlers measured the difference in corneal thickness (in microns) between the two eyes of eight patients. Each patient had one eye that had glaucoma and one eye that was normal. The difference was measured as the corneal thickness of normal eye – corneal thickness of eye with Glaucoma. Corneal thickness is important because it can mask an accurate reading of eye pressure. Use ? = .05. Hypothesis: H0: μd=0Ha: μd≠0 Using output Test statistics : t=0.134P value=0.897 Degrees of freedom (df): df=7 Level of significance: α=0.05 Decision: P value > 0.05 thus we fails to reject null hypothesis. Question a)Write a report summarizing your findings. When writing the report consider that medical staff estimate that a difference of 4.5 microns or more could impact on their ability to interpret eye pressure correctly. b) Define for the hypothesis stated in part b) what a type 1 error and type 2 error would mean. Is it possible…
Calcium is essential to tree growth because it promotes the formation of wood and maintains cell walls. In 1990, the concentration of calcium in precipitation in a certain area was 0.15 milligrams per liter (mg/L). A random sample of 10 precipitation dates in 2007 results in the following data table. Complete parts (a) through (c) below. Click the icon to view the data table. (a) State the hypotheses for determining if the mean concentration of calcium precipitation has changed since 1990. Но Ho: 0.15 mg/L H1: 0.15 mg/L i Data Table (b) Construct a 95% confidence interval about the sample mean concentration of calcium precipitation. The lower bound is The upper bound is (Round to four decimal places as needed.) 0.237 0.067 0.224 0.126 0.081 0.131 0.075 0.171 0.314 0.091 (c) Does the sample evidence suggest that calcium concentrations have changed since 1990? Print Done A. Yes, because the confidence interval does not contain 0.15 mg/L. B. Yes, because the confidence interval contains…
Independent surveys show that the average IQ of 9 r/s babies exposed to cocaine in the uterus is 81 with s.d. 18, while the average IQ of 20 r/s babies unexposed to cocaine in the uterus is 99 with s.d. 9. Construct a 90% c.i. for the difference between the overall average IQs of exposed and unexposed babies. Assume that both populations are normal.
Please circle your answers. Thank you in advanced!
Assuming that the magnitudes are normally distributed, find the percentage of earthquakes with a magnitude higher than 3.18.

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