The earth does not have a uniform mass distribution. The core of the earth has a radius of3490 km and a mass of 1.93 x 102* kg. This is surrounded by the mantle with radii from3490 km to 6345 km and a mass of 4.01 x 1024 kg. Finally, this is all surrounded by thecrust with a thickness of 25 km and a mass of 3.94 × 1022 kg.d. If the earth were instead a sphere with a uniform mass density, show work to find thegravitational acceleration at a radius of 3490 km.

The expression for the gravitational acceleration can be given by, where, G is the gravitational…

The earth does not have a uniform mass distribution. The core of the earth has a radius of 3490 km and a mass of 1.93 x 1024 kg. This is surrounded by the mantle with radii from 3490 km to 6345 km and a mass of 4.01 × 1024 kg. Finally, this is all surrounded by the crust with a thickness of 25 km and a mass of 3.94 x 102² kg.

The earth does not have a uniform mass distribution. The core of the earth has a radius of 3490 km and a mass of 1.93 x 1024 kg. This is surrounded by the mantle with radii from 3490 km to 6345 km and a mass of 4.01 × 1024 kg. Finally, this is all surrounded by the crust with a thickness of 25 km and a mass of 3.94 x 102² kg.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

An element makes up 0.0021% of the Earth's continental crust by mass. Express this in ppm (parts per million), to an appropriate number of significant figures
the average density of an atom is approximately 103 kg/m3. The nucleus of an atom has a radius about 10-5 times that of the entire atom, and contains nearly all the mass of the atom. What is the approximate density, in kilograms per cubic meter, of a nucleus?
2) Find the missing values: (a) 3.0 N1.0 kg 5.0N (b) 2.0N- 120 kg 3.0 N 5.0N -5.0 N -2.0N i- 2.0 m/s? Fret =? a = 0 Ft-? 10 N -5N (d) 30 N- (e) 4000g (f) 5.0 kg 1.0N 2.0N 3.0N constant Fnet ? a-1.5 m/s? - 0.5 m/s? 7, = ? Fret = ? F, = ? -SN 20 N- (h) (i) Fz 30 18 N a = 5 m/s? Fnut = ? a = + 0.6 m/s? Frst = 1.8 × 10-2 N 10 N - constant (down] m-? m= ? Fz = ? net
A homogeneous circular disc with radius R = 5.01 m and thickness t = 16.9·10^−3 m. Calculate the mass of the disc if its density is 6.67 kg / m³.
Question: Two spheres are cut from a certain uniform rock. One has radius 4.40 cm. The mass of the other is two times greater. Find its radius. Answer: cm.
2 Z 2. What is the smallest number of whole logs (density = 760 kg/m³, radius= 0.082 m, length = 2.82 m) that can be used to build a raft that will carry 4 people, each of whom has a mass of 76.5 kg? logs @ 2 W S X H дв command # 3 E D C $ 4 1332 R 20 F G Search or type URL 52 % 5 V T G MacBook Pro 6 B Y H & 7 N U 4 J 1 00 8 - M O ( 9 K O L 1332 jj1332 command P > : t ; { option [ + 11 ? I :- 11
What is the ratio of the surface area to the volume (a) for the 1 m sphere (b) for the 2 m sphere (c) for the 3 m sphere? A) (a) 1/3 (b) 2/3 (c) 1 B) (a) 3 (b) 1.5 (c) 1 C) (a) 1 (b) 1.5 (c) 3 D) (a) 1 (b) 2/3 (c) 1/3
A high tech company uses a satellite to measure the size of features on the surface of the earth. They use this technology to measure a particular rectangular field and find it's length to be 444 ± 1.8 in meters and it's width to be 198 ± 1.63 in meters. They plan to report the perimeter (sum of two lengths and two widths) of the field as P± SP in units of yards. (1 meter = 1.094 yards) What is SP?
The length of the slope of a mountain is 2690 m, and it makes an angle of 10.0° with the horizontal. The height of the mountain relative to its base is
The moon has a mass of 7.34 x 1022 kg and a radius of 1.74x106 m. If you have a mass of 66 kg, how strong is the force between you and the moon?
83184kg = 199.7 mg ball-bearing with arcum ference of 26.1 mm wegs 200mg Circumference of a circle = 2nr)? what is the density of the steel in g/cm³ (u of sphere = 4133 A steel 200mg Ⓡ Deng S (mm) Density = D = Di2g 3 D= masse lume S 062994 cm³ 0.66800267 v=4/7| (4:16mm)³_290-4mm 3 mm³ cm Convert + Tr = 4 tr ² 3 0 C = 2115 C = R 211 2994mm² (1 cm )3 26.1mm = 4.16mm 2 x 3.14 10 mm)³ mg-> conuert 200mg 1000g DRAA 0.2
The sonar unit on a boat is designed to measure the depth of fresh water (p = 1.00 x 103 kg/m³, Bad = 2.20 x 109 Pa). When the boat moves into salt water (p = 1025 kg/m³, Bad = 2.37 x 109 Pa), the sonar unit is no longer calibrated properly. In salt water, the sonar unit indicates the water depth to be 8.87 m. What is the actual depth (in m) of the water? Number i ! Units m