Instructions50 cm10 cm8.0 AR = 1.0 × 10-3 NA small circular loop of wire of radius 5 cm andresistance 1E-3 Q is centered inside a large circularloop of wire of radius 50 cm. The larger loop, whichinitially carries a current of 8 A, is cut and its currentis reduced to zero over a time interval of 1E-6 s. Ourgoal will be to find the average current in the smallerloop during this time interval. (The magnetic field ofthe larger loop is approximately constant over thesmaller loop.) Magnitude of the cross sectionalarea A of the small loop:O 7.9E-3 m2O 3.1E-2 m²O 79 m²O 3.1E2 m2

According to Faraday law Induced emf is the rate of change of magnetic flux. Induced current=…

Answered: Instructions 50 cm 10 cm 8.0 A R = 1.0…

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Instructions 50 cm 10 cm 8.0 A R = 1.0 x 10-3

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

Instructions
50 cm
10 cm
8.0 A
R = 1.0 × 10-3 N
A small circular loop of wire of radius 5 cm and
resistance 1E-3 Q is centered inside a large circular
loop of wire of radius 50 cm. The larger loop, which
initially carries a current of 8 A, is cut and its current
is reduced to zero over a time interval of 1E-6 s. Our
goal will be to find the average current in the smaller
loop during this time interval. (The magnetic field of
the larger loop is approximately constant over the
smaller loop.)

Magnitude of the cross sectional
area A of the small loop:
O 7.9E-3 m2
O 3.1E-2 m²
O 79 m²
O 3.1E2 m2

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