**Problem Description:**The drawing illustrates a frictionless incline and pulley system. Two blocks are connected by a wire with a mass per unit length of 0.0358 kg/m. They are stationary. A transverse wave traveling on the wire moves with a speed of 63.9 m/s. By neglecting the weight of the wire in comparison to the tension within it, calculate the masses:(a) \( m_1 \) (b) \( m_2 \) **Diagram Explanation:**The diagram depicts:- A block \( m_1 \) positioned on a 30.0° incline.- A pulley's rope connecting block \( m_1 \) to block \( m_2 \), which hangs vertically.- Arrows indicate the direction of forces within the system.**Calculation Inputs:**- (a) Mass \( m_1 \) input box with units selector- (b) Mass \( m_2 \) input box with units selector*Note: Ensure to use appropriate physics principles, such as tension in the wire and wave velocity, to find the masses.*

Given, The mass of wire per unit length, m=0.0358 Kg/m The speed of the transverse wave, v=63.9 m/s The angle of inclination, θ=30°Now the equation for both the blocks from Newton's second law of motion will be, For block 1, F-m1gsinθ=0F=m1gsinθ=m1gsin30°=m1g2.............1 For block 2, F-m2g=0F=m2g................2 on putting in the above equation, F=m/Lv2 so mLv2=m1g2m1=2m/Lv2g=2×0.0358×63.929.8=29.832 Kg Hence the mass of block 1 will be, m1=29.832 Kg.The mass of block 2 will be, F=m2gmLv2=m2gm2=m/Lv2g=0.0358×63.929.8=14.9316 Kg Hence the mass of the block m2=14.932 Kg.

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Physics

The drawing shows a frictionless incline and pulley. The two blocks are connected by a wire (mass per unit length = 0.0358 kg/m) and remain stationary. A transverse wave on the wire has a speed of 63.9 m/s. Neglecting the weight of the wire relative to the tension in the wire, find the masses (a) m₁ and (b) m₂ of the blocks. m1 30.0⁰ m2

The drawing shows a frictionless incline and pulley. The two blocks are connected by a wire (mass per unit length = 0.0358 kg/m) and remain stationary. A transverse wave on the wire has a speed of 63.9 m/s. Neglecting the weight of the wire relative to the tension in the wire, find the masses (a) m₁ and (b) m₂ of the blocks. m1 30.0⁰ m2

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Stretched string

A stretched string is a wire which is made up of any metal that must have a larger length compared to its thickness. The ends of the wire are fixed, and when they oscillate or are plucked, it produces two reflected transverse waves of the same frequency and same amplitude. The waves or pulses are traveling in alternate directions and superimpose with one another. This waveform is named standing or stationary waves.

Question

**Problem Description:**

The drawing illustrates a frictionless incline and pulley system. Two blocks are connected by a wire with a mass per unit length of 0.0358 kg/m. They are stationary. A transverse wave traveling on the wire moves with a speed of 63.9 m/s. By neglecting the weight of the wire in comparison to the tension within it, calculate the masses:
(a) \( m_1 \)
(b) \( m_2 \)

**Diagram Explanation:**

The diagram depicts:
- A block \( m_1 \) positioned on a 30.0° incline.
- A pulley's rope connecting block \( m_1 \) to block \( m_2 \), which hangs vertically.
- Arrows indicate the direction of forces within the system.

**Calculation Inputs:**

- (a) Mass \( m_1 \) input box with units selector
- (b) Mass \( m_2 \) input box with units selector

*Note: Ensure to use appropriate physics principles, such as tension in the wire and wave velocity, to find the masses.*

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