The drawing shows 3 resistors of R₁ = 28.0 Q. R₂ = 46.0 02. R3 = 76.0 Q. The current through resistor R3 is 13 = 0.530 A. What is the total voltage V the battery supplies? + R2 V R3 ww 81.4 V 125 V 70.6 V 65.3 V 79.5 V

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**Resistors in a Circuit**

The drawing shows three resistors in a series circuit:
- Resistor \( R_1 = 28.0 \ \Omega \)
- Resistor \( R_2 = 46.0 \ \Omega \)
- Resistor \( R_3 = 76.0 \ \Omega \)

The current through resistor \( R_3 \) is \( I_3 = 0.530 \ A \). The question is: What is the total voltage \( V \) supplied by the battery?

**Circuit Diagram Explanation**

The circuit diagram consists of:
1. A battery symbol with voltage \( V \).
2. Three resistors, \( R_1 \), \( R_2 \), and \( R_3 \), connected in series.
3. The values of the resistors are given and a current \( I_3 \) flowing through \( R_3 \) is specified. 

**Steps to find the total voltage \( V \):**
1. Calculate the total resistance \( R_{\text{total}} \) of the series circuit:
   \[
   R_{\text{total}} = R_1 + R_2 + R_3
   \]
   Substituting the values,
   \[
   R_{\text{total}} = 28.0 \ \Omega + 46.0 \ \Omega + 76.0 \ \Omega = 150.0 \ \Omega 
   \]

2. Use Ohm's Law to find the total voltage \( V \):
   \[
   V = I_{\text{total}} \times R_{\text{total}}
   \]
   where \( I_{\text{total}} = I_3 = 0.530 \ A \).

   Substituting the values,
   \[
   V = 0.530 \ A \times 150.0 \ \Omega = 79.5 \ V
   \]

3. Therefore, the total voltage \( V \) supplied by the battery is \( 79.5 \ V \).

**Given Options:**
- 81.4 V
- 125 V
- 70.6 V
- 65.3 V
- 79.5 V

**Correct Answer:**
- 79.5 V (as indicated by the selection).
Transcribed Image Text:**Resistors in a Circuit** The drawing shows three resistors in a series circuit: - Resistor \( R_1 = 28.0 \ \Omega \) - Resistor \( R_2 = 46.0 \ \Omega \) - Resistor \( R_3 = 76.0 \ \Omega \) The current through resistor \( R_3 \) is \( I_3 = 0.530 \ A \). The question is: What is the total voltage \( V \) supplied by the battery? **Circuit Diagram Explanation** The circuit diagram consists of: 1. A battery symbol with voltage \( V \). 2. Three resistors, \( R_1 \), \( R_2 \), and \( R_3 \), connected in series. 3. The values of the resistors are given and a current \( I_3 \) flowing through \( R_3 \) is specified. **Steps to find the total voltage \( V \):** 1. Calculate the total resistance \( R_{\text{total}} \) of the series circuit: \[ R_{\text{total}} = R_1 + R_2 + R_3 \] Substituting the values, \[ R_{\text{total}} = 28.0 \ \Omega + 46.0 \ \Omega + 76.0 \ \Omega = 150.0 \ \Omega \] 2. Use Ohm's Law to find the total voltage \( V \): \[ V = I_{\text{total}} \times R_{\text{total}} \] where \( I_{\text{total}} = I_3 = 0.530 \ A \). Substituting the values, \[ V = 0.530 \ A \times 150.0 \ \Omega = 79.5 \ V \] 3. Therefore, the total voltage \( V \) supplied by the battery is \( 79.5 \ V \). **Given Options:** - 81.4 V - 125 V - 70.6 V - 65.3 V - 79.5 V **Correct Answer:** - 79.5 V (as indicated by the selection).
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