The drawing shows 3 resistors of R₁ = 28.0 Q. R₂ = 46.0 02. R3 = 76.0 Q. The current through resistor R3 is 13 = 0.530 A. What is the total voltage V the battery supplies? + R2 V R3 ww 81.4 V 125 V 70.6 V 65.3 V 79.5 V
The drawing shows 3 resistors of R₁ = 28.0 Q. R₂ = 46.0 02. R3 = 76.0 Q. The current through resistor R3 is 13 = 0.530 A. What is the total voltage V the battery supplies? + R2 V R3 ww 81.4 V 125 V 70.6 V 65.3 V 79.5 V
College Physics
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ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![**Resistors in a Circuit**
The drawing shows three resistors in a series circuit:
- Resistor \( R_1 = 28.0 \ \Omega \)
- Resistor \( R_2 = 46.0 \ \Omega \)
- Resistor \( R_3 = 76.0 \ \Omega \)
The current through resistor \( R_3 \) is \( I_3 = 0.530 \ A \). The question is: What is the total voltage \( V \) supplied by the battery?
**Circuit Diagram Explanation**
The circuit diagram consists of:
1. A battery symbol with voltage \( V \).
2. Three resistors, \( R_1 \), \( R_2 \), and \( R_3 \), connected in series.
3. The values of the resistors are given and a current \( I_3 \) flowing through \( R_3 \) is specified.
**Steps to find the total voltage \( V \):**
1. Calculate the total resistance \( R_{\text{total}} \) of the series circuit:
\[
R_{\text{total}} = R_1 + R_2 + R_3
\]
Substituting the values,
\[
R_{\text{total}} = 28.0 \ \Omega + 46.0 \ \Omega + 76.0 \ \Omega = 150.0 \ \Omega
\]
2. Use Ohm's Law to find the total voltage \( V \):
\[
V = I_{\text{total}} \times R_{\text{total}}
\]
where \( I_{\text{total}} = I_3 = 0.530 \ A \).
Substituting the values,
\[
V = 0.530 \ A \times 150.0 \ \Omega = 79.5 \ V
\]
3. Therefore, the total voltage \( V \) supplied by the battery is \( 79.5 \ V \).
**Given Options:**
- 81.4 V
- 125 V
- 70.6 V
- 65.3 V
- 79.5 V
**Correct Answer:**
- 79.5 V (as indicated by the selection).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff8c51411-3f37-42fd-90a4-ff7604f0a3a2%2Fa37acdf9-50c6-4c8a-ba3a-e6f3bae5c239%2Funtcqxy_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Resistors in a Circuit**
The drawing shows three resistors in a series circuit:
- Resistor \( R_1 = 28.0 \ \Omega \)
- Resistor \( R_2 = 46.0 \ \Omega \)
- Resistor \( R_3 = 76.0 \ \Omega \)
The current through resistor \( R_3 \) is \( I_3 = 0.530 \ A \). The question is: What is the total voltage \( V \) supplied by the battery?
**Circuit Diagram Explanation**
The circuit diagram consists of:
1. A battery symbol with voltage \( V \).
2. Three resistors, \( R_1 \), \( R_2 \), and \( R_3 \), connected in series.
3. The values of the resistors are given and a current \( I_3 \) flowing through \( R_3 \) is specified.
**Steps to find the total voltage \( V \):**
1. Calculate the total resistance \( R_{\text{total}} \) of the series circuit:
\[
R_{\text{total}} = R_1 + R_2 + R_3
\]
Substituting the values,
\[
R_{\text{total}} = 28.0 \ \Omega + 46.0 \ \Omega + 76.0 \ \Omega = 150.0 \ \Omega
\]
2. Use Ohm's Law to find the total voltage \( V \):
\[
V = I_{\text{total}} \times R_{\text{total}}
\]
where \( I_{\text{total}} = I_3 = 0.530 \ A \).
Substituting the values,
\[
V = 0.530 \ A \times 150.0 \ \Omega = 79.5 \ V
\]
3. Therefore, the total voltage \( V \) supplied by the battery is \( 79.5 \ V \).
**Given Options:**
- 81.4 V
- 125 V
- 70.6 V
- 65.3 V
- 79.5 V
**Correct Answer:**
- 79.5 V (as indicated by the selection).
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