=In the figure R₁ = R₂ = 3.60, R3 = 4.8 Q, R4 = 5.6 0, R5 = 3.4 02, and R6 R7 = Rg = 10.30, and the ideal batteries have emfs 8₁ = 27 V and82 = 10.9 V. What are the (a) magnitude and (b) direction (up or down) of current in and the (c) magnitude and (d) direction of current12? What is the energy transfer rate in (e) battery 1 and (f) battery 2? Is energy being supplied or absorbed in (g) battery 1 and (h)battery 2?(a) Number(b)(c) Number(d)(e) Number(f) NumberIN>jedTwwwwwwR₁RsUnitsUnitsUnitsUnitswwwR₂2wwwR7Rowwwwww wR₁Rg2&1783Rwww

In the figure R₁ = R₂=3.60, R3=4.80, R4 = 5.60, R5 = 3.402, and R6 = R7 = Rg = 10.30, and the ideal batteries have emfs 81 = 27 V and 82= 10.9 V. What are the (a) magnitude and (b) direction (up or down) of current in and the (c) magnitude and (d) direction of current i2? What is the energy transfer rate in (e) battery 1 and (f) battery 2? Is energy being supplied or absorbed in (g) battery 1 and (h) battery 2? R₁ Re www R₂ R₂ Ro www Rg 8₁ 4 R₁ 88%87 04 R₂

In the figure R₁ = R₂=3.60, R3=4.80, R4 = 5.60, R5 = 3.402, and R6 = R7 = Rg = 10.30, and the ideal batteries have emfs 81 = 27 V and 82= 10.9 V. What are the (a) magnitude and (b) direction (up or down) of current in and the (c) magnitude and (d) direction of current i2? What is the energy transfer rate in (e) battery 1 and (f) battery 2? Is energy being supplied or absorbed in (g) battery 1 and (h) battery 2? R₁ Re www R₂ R₂ Ro www Rg 8₁ 4 R₁ 88%87 04 R₂

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Question

=
In the figure R₁ = R₂ = 3.60, R3 = 4.8 Q, R4 = 5.6 0, R5 = 3.4 02, and R6 R7 = Rg = 10.30, and the ideal batteries have emfs 8₁ = 27 V and
82 = 10.9 V. What are the (a) magnitude and (b) direction (up or down) of current in and the (c) magnitude and (d) direction of current
12? What is the energy transfer rate in (e) battery 1 and (f) battery 2? Is energy being supplied or absorbed in (g) battery 1 and (h)
battery 2?
(a) Number
(b)
(c) Number
(d)
(e) Number
(f) Number
IN
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T
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www
R₁
Rs
Units
Units
Units
Units
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R₂
2
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R7
Ro
www
www w
R₁
Rg
2
&17
83
R
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Expert Solution

Step 1

Since we answer up to three subparts, we will answer the first three. Please resubmit the question and specify the other subparts you would like to get answered.

The resistors $R_{7} and R_{8}$ are connected in parallel, so the equivalent resistance of these two resistors are

$R_{78} = \frac{R_{8} R_{7}}{R_{8} + R_{7}} R_{78} = \frac{10.3 Ω \times 10.3 Ω}{10.3 Ω + 10.3 Ω} R_{78} = 5.15 Ω$

Now the resistors $R_{78}, R_{1} and R_{2}$ are in series, the equivalent resistance is

$R_{7812} = R_{78} + R_{1} + R_{2} R_{7812} = 5.15 Ω + 3.6 Ω + 3.6 Ω R_{7812} = 12.35 Ω$

Now $R_{7812} and R_{6}$ is parallel, the equivalent resistance is

$R_{78126} = \frac{R_{7812} R_{6}}{R_{7812} + R_{6}} R_{78126} = \frac{12.35 Ω \times 10.3 Ω}{12.35 Ω + 10.3 Ω} R_{78126} = 5.62 Ω$

Now the circuit becomes

Here $I_{1} a n d I_{2}$ are the currents in loop

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