The double - riveted joint connects two plates which are each 3.0 mm thick, and the rivets have a diameter of 4 mm., if the failure strength of the rivets in shear is 370 N/mm? and the ultimate tensile strength of the plate is 465 N/mm?, determine the necessary rivet pitch b (mm) if the joint is to be designed so that failure due to shear in the rivets and failure due to tension in the plate occur simultaneously. Calculate also the joint efficiency n (%). 3 mm 4 mm diameter

The double - riveted joint connects two plates which are each 3.0 mm thick, and the rivets have a diameter of 4 mm., if the failure strength of the rivets in shear is 370 N/mm? and the ultimate tensile strength of the plate is 465 N/mm?, determine the necessary rivet pitch b (mm) if the joint is to be designed so that failure due to shear in the rivets and failure due to tension in the plate occur simultaneously. Calculate also the joint efficiency n (%). 3 mm 4 mm diameter

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: A plate having a width of 400 and a thickness of 20mm is to be connected to two plates with…

Q: The plate welded to the end of the I-beam is fastened to the support with four 10-mm-diameter bolts…

A: The data given is a I beam inclined at 40o subjected to a 30 kN force, and is supported by two bolts…

Q: 8. The assembly consists of a steel bar A (Ast= 500 mm2, Est= 200 GPa, and aAL= 12 x 10-6), a rigid…

Q: Q1/ Find the value of P for the joint shown in the figure if the allowable shear stress is 100 MPa…

A: given value are, ζ=100 Mpa and diameter D=20 mm n=4 direct shear stress on each rivet, Ps=PnPs=…

Q: The steel assembly is constructed with a 0.25-inch-diameter pin at C and with 0.5-inch- diameter…

A: Given , Tult , pin = 22 ksi σult = 58 ksiAlso , FOS = σult σall = Tult Tall…

Q: A solid brass E = 100 GPa axial member is loaded and supported as shown in the figure. Segments (1)…

A: Given data, W1 = 35 kN W2 = 14 kN W3 = 28 kN E = 100 GPa L1 = 1.8m L2 = 1.2 m L3 = 1.6 m To find…

Q: The assembly consists of two red brass C83400 copper rods AB and CD having a diameter of 30 mm, a…

A: Figure is as shown

Q: The stress field in a loaded aluminum plate was determined as [-2x² + 3y² 3x + y+ 5] O = F[3x + y+5…

Q: The plates in the figure below are each 3 inches by 0.5 inches in cross section. If the hole in each…

A: Solution:- Given information: Cross section of plate =3×0.5 in Hole diameter, d=1316 in, and Load,…

Q: If the eyebolt is made of a material having a yield stress of Y = 275 MPa and the factor of safety…

A: The given data is: Yield stress (σy) = 275 MPa FS = 1.45

Q: 4.) A 150 x 90 x 12 angular section is welded to a gusset plate as shown in the figure. The angle is…

A: To Determine Design force, P

Q: A 12.5-mm round structural steel rod is loaded in tension to fracture. The 200-mm gage length of…

A: ASKED: To compute the average strain for the steel rod. Given, Gage length of the rod (L) = 200 mm…

Q: A W18×86 beam is riveted tona W24×117 grinder by q connection as shown in the figure. The diameter…

A: Bearing strength is the maximum stress load that the unit can hold before the structure fails. But…

Q: 8 ksi, øy = -4 ks The normal stresses at a point in a steel member are ox 10 ksi. Using E = 29 × 10³…

A: Given data in question Stresses Elasticity modulus Poissons ratio To find out Normal strains

Concept explainers

Members with compression and bending

Compression members are structural elements that carry compressive axial force. They are the vertical members of a building that support beams and their design, which is governed by buckling and strength. Columns are known as struct or compression members, which are subjected to compressive forces. These members provide stiffness to the building and avoid any imperfection regarding the transfer of axial load. For instance, webs in a truss, braces in a framed structure, tiers, and so on.

Question

The double - riveted joint connects two plates which are each 3.0 mm thick, and the rivets
have a diameter of 4 mm., if the failure strength of the rivets in shear is 370 N/mm2 and the
ultimate tensile strength of the plate is 465 N/mm?, determine the necessary rivet pitch b
(mm) if the joint is to be designed so that failure due to shear in the rivets and failure due to
tension in the plate occur simultaneously. Calculate also the joint efficiency n (%).
3 mm
4 mm diameter

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

Someone can help me with these. I'm stock, please.
Question 4. Three wires are used to suspend the plate shown. Aluminium wires are used at A and B with a diameter of 3 mm and a steel wire is used at C with a diameter of 2 mm. Knowing that the allowable stress for aluminium (E = 72 GPa) is 96 MPa and that the allowable stress for steel (E = 200 GPa) is 124 MPa, determine the maximum load P that may be applied. L L P B
please help me to design a simple tensile structure for the exhibition space roof
The member consists of the steel rod AB that is screwed into the end of the bronze rod BC. Find the largest value of P that meets the following design criteria: (i) the overall length of the member is not to change by more than 3 mm; and (ii) the stresses are not to exceed 140 MPa in steel and 120 MPa in bronze. The moduli of elasticity are 200 GPa for steel and 80 GPa for bronze. A Steel 1.0 m A = 480 mm² В 3P Bronze A = 650 mm² 2 m 2P
A channel-section has the dimensions as shown. 3) Consider a cantilevered beam subjected to an end force P. Cr (a) if cross L = 100 cm ction in is used determine its normal stress 2 2ºM 8⁰m 2cm
An aluminium wire (E=10,600 ksi) having a diameter d=1/8 inch. and length L=14 ft is subjected to a tensile load P. If the maximum permissible elongation of the wire is 1/6 inch and the allowable stress in tension is 10 ksi, what is the allowable load Pmax? Answer in Ibs
The 10-mm-diameter steel bolt in (Figure 1) is surrounded by a bronze sleeve. The outer diameter of this sleeve is 20 mm, and its inner diameter is 10 mm. Est = 200 GPa, Ebr 100 GPa. Figure P P -10 mm -20 mm 1 of 1 Part A If the bolt is subjected to a compressive force of P = 21.9 kN, determine the magnitude of the average normal stress in the steel. Express your answer to three significant figures and include appropriate units. Ost = Submit Part B Obr = Submit 0 Value If the bolt is subjected to a compressive force of P = 21.9 kN, determine the magnitude of the average normal stress in the bronze. Express your answer to three significant figures and include appropriate units. Provide Feedback A Request Answer Value Units Request Answer Units ?
Steel
Two aluminum plates, each having a width b = 7.5” and thickness t = 2”, are welded together as shown in the figure. Assume that a = 5.0”. Specifications require that the normal and shear stress magnitudes acting in the weld material may not exceed 40 ksi and 25 ksi, respectively.
The member consists of the steel rod AB that is screwed into the end of the bronze rod BC. Find the largest value of P that meets the following design criteria: (i) the overall length of the member is not to change by more than 3 mm; and (ii) the stresses are not to exceed 140 MPa in steel and 120 MPa in bronze. The moduli of elasticity are 200 GPa for steel and 80 GPa for bronze
I need the answer as soon as possible
A brass sleeve S is fitted over a steel bolt B, and the nut is tightened until it is just snug. The bolt has a diameter of dB = 25 mm, and the sleeve has inside and outside diameters of d1 = 26 mm and d2 = 36 mm, respectively. d2 di dB Sleeve (S) Bolt (B) Calculate the temperature rise AT that is required to produce a compressive stress of 23 MPa in the sleeve. (Use material properties as follows: for the sleeve, as = 21 x 10-6/C and Es = 200 GPa; for the bolt, aB = 10 × 10¬6/°C and EB = 400 GPa.) AT = °C (Round to the nearest whole number.)