A brass sleeve S is fitted over a steel bolt B, and the nut is tightened until it is just snug. The bolt has a diameter of dB = 25 mm, and the sleeve has inside and outside diameters of d1 = 26 mmand d2 = 36 mm, respectively.d2didBSleeve (S)Bolt (B)Calculate the temperature rise AT that is required to produce a compressive stress of 23 MPa in the sleeve. (Use material properties as follows: for the sleeve, as = 21 x 10-6/C andEs = 200 GPa; for the bolt, aB = 10 × 10¬6/°C and EB= 400 GPa.)AT =°C (Round to the nearest whole number.)

To determine the rise in temperature that would cause a given compressive stress in the brass sleeve…

A brass sleeve S is fitted over a steel bolt B, and the nut is tightened until it is just snug. The bolt has a diameter of de = 25 mm, and the sleeve has inside and outside diameters of d = 26 mm and d2 = 36 mm, respectively. d2 Sleeve (S). dB Bolt (B) Calculate the temperature rise AT that is required to produce a compressive stress of 23 MPa in the sleeve. (Use material properties as follows: for the sleeve, as = 21 × 10-6/°C and Es = 200 GPa; for the bolt, ag = 10 × 10-6/°C and Eg = 400 GPa.)

A brass sleeve S is fitted over a steel bolt B, and the nut is tightened until it is just snug. The bolt has a diameter of de = 25 mm, and the sleeve has inside and outside diameters of d = 26 mm and d2 = 36 mm, respectively. d2 Sleeve (S). dB Bolt (B) Calculate the temperature rise AT that is required to produce a compressive stress of 23 MPa in the sleeve. (Use material properties as follows: for the sleeve, as = 21 × 10-6/°C and Es = 200 GPa; for the bolt, ag = 10 × 10-6/°C and Eg = 400 GPa.)

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Two circular shafts are joined together between fixed supports to resist a torsional moment of 80 kN-m as shown. Determine the absolute value of the maximum torsional shear stress of the hollow steel shaft (in MPa). 20 IN-m Sm stcel hellw circalar duminum Selid circular D= 75 mny Do- IDO mn D> 80 mm G- D GPon 6- IS0 EPa
The two wooden boards are connected by a 0.7 in. diameter bolt. Washers are installed under the head of the bolt and under the nut. The washer dimensions are D = 2.4 in. and d = 0.8 in. The nut is tightened to cause a tensile stress of 12000 psi in the bolt. Determine the bearing stress between the washer and the wood. Answer: Ob = i Bolt D Washer psi - Washer Nut
Q2: aluminum rod AB (G 27GPA) brass rod BD (G = 39GPA). portion CD of the brass rod is hollow and has an inner diameter of 40 mm, Determine: a) the angle of twist at A. b) maximum shear stress of rod AD c) torque diagram d) angle of twist diagram
The 10-mm-diameter steel bolt is surrounded by a bronze sleeve. The outer diameter of this sleeve is 20 mm, and its inner diameter is 10 mm. If the yield stress for the steel is (ay) MPa, and for the bronze (ay)or 520 MPa, determine the magnitude of the largest elastic load P 640 that can be applied to the assembly. E 200 GPa, Ebr= 100 GPa. 10 mm 20 mm Figure 2: Steel Bolt
4-82. The 50-mm-diameter cylinder is made from Am 1004-T61 magnesium and is placed in the clamp when the temperature is T₁ = 15°C. If the two 304 stainless steel carriage bolts of the clamp each have a diameter of 10 mm, and they hold the cylinder snug with negligible force against the rigid jaws, determine the temperature at which the average normal stress in either the magnesium or the steel first becomes 12 MPa. 100 mm Probs. 4-81/82 150 mm
The screw clamp shown in the figure applies a P = 500 N pressing force to the wooden blocks between the jaws. In this case; a) Calculate the greatest tensile and compressive stresses occurring in the section a-a shown in the figure. b) Show the distribution of normal stresses across the section height. (draw) c) Since the clamp material has tensile strength (apull) safety = 50MPA and compression safe stress (opress) safety = 80MPA, what is the great compressive load (P) that can be applied without damaging the a-a section? %3D %3D (Please solve in detail and according to engineering rules.) Material mechanics Sectional view a-a - 20mm T. 183mm 40mm
The pressure tank is fabricated from spirally wrapped metal plates that are welded at the seams in the orientation shown. The tank has an inside diameter of 700 mm and a wall thickness of 9.5 mm. For a gage pressure of 0.83 MPa, determine (a) the normal stress perpendicular to the weld (use positive for tension, negative for compression) and (b) the shear stress (absolute value) parallel to the weld. Assume β=32∘
A plate with width of 420 mm and thickness of 13 mm is to be connected to a plate of the same width and thickness by 30 mm diameter bolts, as shown in the Figure 1. The holes are 3mm larger than the bolt diameter. The plate is A36 steel with yield strength Fy = 248MPa. Assume allowable tensile stress on net area is 0.60Fy. It is required to determine the value of b such that the net width along bolts 1-2-3-4 is equl to the net width along bolts 1-2-4. W = 420 mm t = 13 mm a = 64 mm c = 104 mm d = 195 mm Bolt Diameter = 30 mm Holes Diameter = 30 mm + 3 = 33 mm ?? = 248 MPa Allowable Tensile Stress on ?? = 0.60Fy a. Calculate the vaue of b in millimeters. b. Calculate the value of the net area for tension in plates in square millimeters. c. Calculate the value of P so that the allowable tensile stress on net area will not be exceeded.
The solid rod has a diameter of 20mm. Find the following: Angle of twist at C with respect to A (in radians) Angle of twist at B with respect to A (in radians) Maximum shear stress at A (in MPa) (Shear stress at support, at a point 7mm from center. (in MPa) A-36 steel with the following properties: Modulus of Elasticity, E = 29x10^3 ksi or 200 GPa Shear Modulus/Modulus of Rigidity, G = 11.5x10^3 ksi or 79.3 GPa Poisson's Ratio, nu = 0.260 Temperature Coefficient for thermal expansion, a = 6.6x10^-6/°F or 11.7x10^-6/°C
An A36 steel plate with width of 400 mm and thickness of 12 mm is to beconnected to a plate of the same width and thickness by 34 mm diametersbolts, as shown in the figure (next slide). The holes are 2 mm larger thanthe bolt diameter. The yield strength of the steel plate is Fy = 248 MPa.Assume allowable tensile stress on net area is 0.60Fy. It is required todetermine the value of b such that the net width along bolts 1-2-3-4 isequal to the net width along bolts 1-2-4.a. Calculate the value of b in mm.b. Calculate the value of the net area for tension in plates in mm².c. Calculate the value of P so that the allowable tensile stress on net areawill not be exceeded.(Use at least 2 decimal points on your answers.)
Required information Consider the loading shown. The allowable normal stress for the steel used is 160 MPa. 0.8 m 50 kN/m B -2.4 m- 0.8 m For the selected design, determine the actual value of Om in the beam. (Round the final answer to one decimal place. You must provide an answer before moving to the next part.) The actual value of om in the beam is 160 MPa.
What is the manufacturing tensional yield strength (lbf) of grade S135 drill pipe? a. This is a trick question because drill pipe size is not provided b. The answer can’t be calculated because the length of the pipe is not given c. The yield strength is 135000 psi and is a property of the steel d. The yield strength is 135000 psi and depends on the cross-sectional area