Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Educational Resource on Unit Conversion:**
---
**Converting the Distance Between Oxygen Atoms**
**Problem Statement:**
The distance between the centers of two oxygen atoms in an oxygen molecule is \(1.21 \times 10^{-8}\) cm. What is this distance in nm?
**Tools Provided:**
- Various numerical values and scientific notations.
- Unit conversion factors.
**Methodology:**
To convert from centimeters (cm) to nanometers (nm), you need to use the appropriate unit conversion factor.
1. **Starting Amount:**
- \( 1.21 \times 10^{-8} \text{ cm} \)
2. **Conversion Factor:**
- \( 1 \text{ cm} = 10^7 \text{ nm} \)
**Steps to solve:**
1. Multiply the starting amount by the conversion factor:
\[
1.21 \times 10^{-8} \text{ cm} \times 10^7 \text{ nm/cm}
\]
2. Combine the exponents and simplify:
\[
1.21 \times 10^{-8} \times 10^7 = 1.21 \times 10^{-1} \text{ nm}
\]
So, the distance between the centers of the two oxygen atoms in nanometers is \( 1.21 \times 10^{-1} \text{ nm} \) or \( 0.121 \text{ nm} \).
**Interactive components:**
1. **Starting Amount Box:** Enter \(1.21 \times 10^{-8}\).
2. **Add Factor Box:** Add the conversion factor \(10^7\).
3. **Answer Box:** This should display the calculation result \(0.121\) after clicking the "equal" button.
**Buttons Available:**
- Numerical values (e.g., \(100, 10^6, 10^{-6}, 1.21 \times 10^{-15}, 0.01, 10^9, 1, 0.0121, 1.21, 0.121, 10^{-9}\))
- Units (m, cm, nm)
**Reset Button:** This allows you to clear the entered values and start a new calculation.
**Graphical Overview:**
There are no graphical data such as bar graphs or line charts present.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9c611bf3-375a-4bcc-90fb-aaa1871cff40%2F5686c337-26fc-4615-8549-902626f4587a%2Fx77yb6b_reoriented.jpeg&w=3840&q=75)
Transcribed Image Text:**Educational Resource on Unit Conversion:**
---
**Converting the Distance Between Oxygen Atoms**
**Problem Statement:**
The distance between the centers of two oxygen atoms in an oxygen molecule is \(1.21 \times 10^{-8}\) cm. What is this distance in nm?
**Tools Provided:**
- Various numerical values and scientific notations.
- Unit conversion factors.
**Methodology:**
To convert from centimeters (cm) to nanometers (nm), you need to use the appropriate unit conversion factor.
1. **Starting Amount:**
- \( 1.21 \times 10^{-8} \text{ cm} \)
2. **Conversion Factor:**
- \( 1 \text{ cm} = 10^7 \text{ nm} \)
**Steps to solve:**
1. Multiply the starting amount by the conversion factor:
\[
1.21 \times 10^{-8} \text{ cm} \times 10^7 \text{ nm/cm}
\]
2. Combine the exponents and simplify:
\[
1.21 \times 10^{-8} \times 10^7 = 1.21 \times 10^{-1} \text{ nm}
\]
So, the distance between the centers of the two oxygen atoms in nanometers is \( 1.21 \times 10^{-1} \text{ nm} \) or \( 0.121 \text{ nm} \).
**Interactive components:**
1. **Starting Amount Box:** Enter \(1.21 \times 10^{-8}\).
2. **Add Factor Box:** Add the conversion factor \(10^7\).
3. **Answer Box:** This should display the calculation result \(0.121\) after clicking the "equal" button.
**Buttons Available:**
- Numerical values (e.g., \(100, 10^6, 10^{-6}, 1.21 \times 10^{-15}, 0.01, 10^9, 1, 0.0121, 1.21, 0.121, 10^{-9}\))
- Units (m, cm, nm)
**Reset Button:** This allows you to clear the entered values and start a new calculation.
**Graphical Overview:**
There are no graphical data such as bar graphs or line charts present.
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