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The displacements for the truss shown in Figure P19.7 are U = 0.0 U2= 0.0 U4=-0.3333 U3= 1.748 Us=-0.5000 U6= 0.0 Us=-3.690 U7= 2.248 The area of each member in square centimeters is underlined. The ler dimensions are in centimeters and each member is made from steel, 20(106) N/cm?. Calculate the axial force in each member connecte joint two and show that this joint is in equilibrium. There is no temper= change. (4) 10 4 10 15 (3) 15 200- 500 (5) (1) (2) 10 3 1 2.

The displacements for the truss shown in Figure P19.7 are U = 0.0 U2= 0.0 U4=-0.3333 U3= 1.748 Us=-0.5000 U6= 0.0 Us=-3.690 U7= 2.248 The area of each member in square centimeters is underlined. The ler dimensions are in centimeters and each member is made from steel, 20(106) N/cm?. Calculate the axial force in each member connecte joint two and show that this joint is in equilibrium. There is no temper= change. (4) 10 4 10 15 (3) 15 200- 500 (5) (1) (2) 10 3 1 2.

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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The displacements for the truss shown in Figure P19.7 are U = 0.0 U2= 0.0 U4=-0.3333 U3= 1.748 Us=-0.5000 U6= 0.0 Ug=-3.690 U7= 2.248 The area of each member in square centimeters is underlined. The length dimensions are in centimeters and each member is made from steel, E= 20(10°) N/cm?. Calculate the axial force in each member connected to joint two and show that this joint is in equilibrium. There is no temperature change. 2 (4) 10 4 10 15 (3) 15 200 kN 500 (5) (1) (2) 10 3 500- 500
Transcribed Image Text:The displacements for the truss shown in Figure P19.7 are U = 0.0 U2= 0.0 U4=-0.3333 U3= 1.748 Us=-0.5000 U6= 0.0 Ug=-3.690 U7= 2.248 The area of each member in square centimeters is underlined. The length dimensions are in centimeters and each member is made from steel, E= 20(10°) N/cm?. Calculate the axial force in each member connected to joint two and show that this joint is in equilibrium. There is no temperature change. 2 (4) 10 4 10 15 (3) 15 200 kN 500 (5) (1) (2) 10 3 500- 500
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