The diffusion coefficient of valine in water at 298 KKis 0.831×10−9m2⋅s−10.831×10−9m2⋅s−1. Determine the time it will take a valine molecule on average to diffuse an rms distance of 2.00. If the molecular diameter of valine is taken to be 0.300 nmnm, what is the time per random walk step? Thermo - Problem 17.47 of 13II Review I Constants I Periodic TablThe diffusion coefficient of valine in water at 298 KDetermine the time it will take a valine molecule on average to diffuse an rms distance of 2.00 mm.is 0.831 × 10–9 m² · s-1.Express your answer in seconds to three significant figures.?t =SSubmitRequest AnswerPart BIf the molecular diameter of valine is taken to be 0.300 nm,what is the time per random walk step?Express your answer in seconds to three significant figures.ΑΣφT =SP Pearson

The equation of time taken by a molecule is derived from Pythagorean theorem under assumption that diffusion is equivalent in all three dimensions is shown below. r=6Dtt=r26D Here, r is the room mean square displacement, t is the time, D is the diffusion coefficient.Given: r=2.00 mm = 2 x 10-3 m D = 0.831×10−9m2⋅s−1 The time taken by the valine molecule is calculated as follows: t=2×10-3m26×0.831×10-9m2s-1 =802.25 s Thus, the required time taken by a valine molecule is 802.25 s. Now, if the diameter of valine is 0.300 nm = 0.300 x 10-9 m. The time per random walk step is calculated by the equation shown below. D=x∘22t≈d22t Here, xo is the average distance, t is the time, D is the diffusion coefficient, d is the diameter. Now, we will substitute all the values in the above equation: t=0.300×10-9m22×0.831×10-9m2s-1 =5.41×10-11s Hence, the time per random walk step is 5.41 x 10-11s.