Carbon tetrachloride (CC14) is diffusing through benzene (C6H6), as the drawing illustrates. The concentration of CCl4 at the left end of the tube is maintained at 1.95 x 10-2 kg/m3, and the diffusion constant is 20.4 x 10-10 m²/s. The CCl4 enters the tube at a mass rate of 4.52 x 10-13 kg/s. Using these data and those shown in the drawing, find (a) the mass of CCl4 per second that passes point A and (b) the concentration of CCl4 at point A. (a) Number P i (b) Number i Units Units 5.00x 10-3 m -CCIA Cross-sectional area = 3.00 x 104 m²
Carbon tetrachloride (CC14) is diffusing through benzene (C6H6), as the drawing illustrates. The concentration of CCl4 at the left end of the tube is maintained at 1.95 x 10-2 kg/m3, and the diffusion constant is 20.4 x 10-10 m²/s. The CCl4 enters the tube at a mass rate of 4.52 x 10-13 kg/s. Using these data and those shown in the drawing, find (a) the mass of CCl4 per second that passes point A and (b) the concentration of CCl4 at point A. (a) Number P i (b) Number i Units Units 5.00x 10-3 m -CCIA Cross-sectional area = 3.00 x 104 m²
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Text Transcription for Educational Website:**
**Carbon Tetrachloride Diffusion Through Benzene**
Carbon tetrachloride (CCl₄) is diffusing through benzene (C₆H₆). According to the illustration, the concentration of CCl₄ at the left end of the tube is maintained at 1.95 x 10⁻² kg/m³, and the diffusion constant is 20.4 x 10⁻¹⁰ m²/s. The CCl₄ enters the tube at a mass rate of 4.52 x 10⁻¹³ kg/s. Using these data and those shown in the drawing, find:
(a) The mass of CCl₄ per second that passes point A.
(b) The concentration of CCl₄ at point A.
**Diagram Explanation:**
The diagram shows a tube through which carbon tetrachloride (CCl₄) is diffusing. The left section of the tube is highlighted in red, representing the entry point of CCl₄. The tube has a cross-sectional area of 3.00 x 10⁻⁴ m² and a length of 5.00 x 10⁻³ m from the entry point to point A. The illustration aims to help visualize the diffusion process and aids in calculating the diffusion rate and concentration changes within the tube.
**Questions:**
(a) Number [Input] Units [Select from list]
(b) Number [Input] Units [Select from list]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd452bd8c-7554-4806-a6d8-accf0f380aea%2Feb5ef718-998e-4718-9c10-d9f4e1b1bf5c%2Fv6awwcm_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Text Transcription for Educational Website:**
**Carbon Tetrachloride Diffusion Through Benzene**
Carbon tetrachloride (CCl₄) is diffusing through benzene (C₆H₆). According to the illustration, the concentration of CCl₄ at the left end of the tube is maintained at 1.95 x 10⁻² kg/m³, and the diffusion constant is 20.4 x 10⁻¹⁰ m²/s. The CCl₄ enters the tube at a mass rate of 4.52 x 10⁻¹³ kg/s. Using these data and those shown in the drawing, find:
(a) The mass of CCl₄ per second that passes point A.
(b) The concentration of CCl₄ at point A.
**Diagram Explanation:**
The diagram shows a tube through which carbon tetrachloride (CCl₄) is diffusing. The left section of the tube is highlighted in red, representing the entry point of CCl₄. The tube has a cross-sectional area of 3.00 x 10⁻⁴ m² and a length of 5.00 x 10⁻³ m from the entry point to point A. The illustration aims to help visualize the diffusion process and aids in calculating the diffusion rate and concentration changes within the tube.
**Questions:**
(a) Number [Input] Units [Select from list]
(b) Number [Input] Units [Select from list]
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