Carbon tetrachloride (CC14) is diffusing through benzene (C6H6), as the drawing illustrates. The concentration of CCl4 at the left end of the tube is maintained at 1.95 x 10-2 kg/m3, and the diffusion constant is 20.4 x 10-10 m²/s. The CCl4 enters the tube at a mass rate of 4.52 x 10-13 kg/s. Using these data and those shown in the drawing, find (a) the mass of CCl4 per second that passes point A and (b) the concentration of CCl4 at point A. (a) Number P i (b) Number i Units Units 5.00x 10-3 m -CCIA Cross-sectional area = 3.00 x 104 m²

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Chapter1: Chemical Foundations
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**Text Transcription for Educational Website:**

**Carbon Tetrachloride Diffusion Through Benzene**

Carbon tetrachloride (CCl₄) is diffusing through benzene (C₆H₆). According to the illustration, the concentration of CCl₄ at the left end of the tube is maintained at 1.95 x 10⁻² kg/m³, and the diffusion constant is 20.4 x 10⁻¹⁰ m²/s. The CCl₄ enters the tube at a mass rate of 4.52 x 10⁻¹³ kg/s. Using these data and those shown in the drawing, find:

(a) The mass of CCl₄ per second that passes point A.

(b) The concentration of CCl₄ at point A.

**Diagram Explanation:**

The diagram shows a tube through which carbon tetrachloride (CCl₄) is diffusing. The left section of the tube is highlighted in red, representing the entry point of CCl₄. The tube has a cross-sectional area of 3.00 x 10⁻⁴ m² and a length of 5.00 x 10⁻³ m from the entry point to point A. The illustration aims to help visualize the diffusion process and aids in calculating the diffusion rate and concentration changes within the tube.

**Questions:**

(a) Number [Input] Units [Select from list]

(b) Number [Input] Units [Select from list]
Transcribed Image Text:**Text Transcription for Educational Website:** **Carbon Tetrachloride Diffusion Through Benzene** Carbon tetrachloride (CCl₄) is diffusing through benzene (C₆H₆). According to the illustration, the concentration of CCl₄ at the left end of the tube is maintained at 1.95 x 10⁻² kg/m³, and the diffusion constant is 20.4 x 10⁻¹⁰ m²/s. The CCl₄ enters the tube at a mass rate of 4.52 x 10⁻¹³ kg/s. Using these data and those shown in the drawing, find: (a) The mass of CCl₄ per second that passes point A. (b) The concentration of CCl₄ at point A. **Diagram Explanation:** The diagram shows a tube through which carbon tetrachloride (CCl₄) is diffusing. The left section of the tube is highlighted in red, representing the entry point of CCl₄. The tube has a cross-sectional area of 3.00 x 10⁻⁴ m² and a length of 5.00 x 10⁻³ m from the entry point to point A. The illustration aims to help visualize the diffusion process and aids in calculating the diffusion rate and concentration changes within the tube. **Questions:** (a) Number [Input] Units [Select from list] (b) Number [Input] Units [Select from list]
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