The differential equation used to model population growth, under the assumption that the proportional growth rate is a decreasing linear function of population, is the logistic differential equation dP = rP(1 − ) dt where r and M are positive constants. By the change of variables, P(t) = Mx(t) we can obtain the simpler, related differential equation d² = rx(1 − x) for x > 0. (a) Express (1¹) in partial fraction form; hence find ſz(1¹) dæ, expressing your answer in the form In(). (Make sure you consider the two cases x < 1 and x > 1 separately.) (b) If x= xo> 0 when t = 0, show that the solution of the equation is 1 1+ (−1)e-ri (c) Considering the two cases xo < 1 and xo > 1, determine what happens in the long run. x p-rt

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Chapter2: Second-order Linear Odes
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2 The differential equation used to model population growth, under the assumption that the proportional
growth rate is a decreasing linear function of population, is the logistic differential equation
dP
d = rP(1 - )
where r and M are positive constants. By the change of variables, P(t) = Mx(t) we can obtain the simpler,
related differential equation
d = rx(1-x)
for x > 0.
(a) Express (1-2) in partial fraction form; hence find (1-2) dx, expressing your answer in the form
In(). (Make sure you consider the two cases x < 1 and x >1 separately.)
(b) If x= xo> 0 when t = 0, show that the solution of the equation is
X =
1
1 + (1 - 1)e-rt
(c) Considering the two cases xo < 1 and xo > 1, determine what happens in the long run.
(d) What happens if xo = 0 or xo = 1?
Transcribed Image Text:2 The differential equation used to model population growth, under the assumption that the proportional growth rate is a decreasing linear function of population, is the logistic differential equation dP d = rP(1 - ) where r and M are positive constants. By the change of variables, P(t) = Mx(t) we can obtain the simpler, related differential equation d = rx(1-x) for x > 0. (a) Express (1-2) in partial fraction form; hence find (1-2) dx, expressing your answer in the form In(). (Make sure you consider the two cases x < 1 and x >1 separately.) (b) If x= xo> 0 when t = 0, show that the solution of the equation is X = 1 1 + (1 - 1)e-rt (c) Considering the two cases xo < 1 and xo > 1, determine what happens in the long run. (d) What happens if xo = 0 or xo = 1?
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