The amount of fish in a lake is modeled by the logistic equation: = 2y(4 – y). If a certain amount of fish k is caught per unit of time, the equation becomes y = 2y(4 – 3) – k, k > 0. (a) Determine for which h the equation has two, one, and no equilibriums respectively. (b) Let h be such that the equation has one equilibrium. Find out for which initial amount of fish y(0) the population will eventually die out, and for which it will not. Sketch solution curves. (C) For k = 6, find equilibriums and study their stability. Sketch solution curves. Find the solution with initial condition y(0) = 2.

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The amount of fish in a lake is modeled by the logistic equation: y' = 2y(4 – y). If a certain amount of fish k is caught per unit of time, the
equation becomes y' = 2y(4 – 3) – k, k > 0.
(a) Determine for which h the equation has two, one, and no equilibriums respectively.
(b) Let h be such that the equation has one equilibrium. Find out for which initial amount of fish y(0) the population will eventually die out, and
for which it will not. Sketch solution curves.
(C) For k = 6, find equilibriums and study their stability. Sketch solution curves. Find the solution with initial condition y(0) = 2.
Transcribed Image Text:The amount of fish in a lake is modeled by the logistic equation: y' = 2y(4 – y). If a certain amount of fish k is caught per unit of time, the equation becomes y' = 2y(4 – 3) – k, k > 0. (a) Determine for which h the equation has two, one, and no equilibriums respectively. (b) Let h be such that the equation has one equilibrium. Find out for which initial amount of fish y(0) the population will eventually die out, and for which it will not. Sketch solution curves. (C) For k = 6, find equilibriums and study their stability. Sketch solution curves. Find the solution with initial condition y(0) = 2.
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