The differential equation below models the temperature of a 87°C cup of coffee in a 23°C room, where it is known that the coffee cools at a rate of 1°C per minute when its temperature is 73°C. Solve the differential equation to find an expression for the temperature of the coffee at time t. (Let y be the temperature of the cup of coffee in °C and let t be the time in minutes, with t = 0 corresponding to the time when the temperature was 87°C.) dy dt = − 1 50
The differential equation below models the temperature of a 87°C cup of coffee in a 23°C room, where it is known that the coffee cools at a rate of 1°C per minute when its temperature is 73°C. Solve the differential equation to find an expression for the temperature of the coffee at time t. (Let y be the temperature of the cup of coffee in °C and let t be the time in minutes, with t = 0 corresponding to the time when the temperature was 87°C.) dy dt = − 1 50
The differential equation below models the temperature of a 87°C cup of coffee in a 23°C room, where it is known that the coffee cools at a rate of 1°C per minute when its temperature is 73°C. Solve the differential equation to find an expression for the temperature of the coffee at time t. (Let y be the temperature of the cup of coffee in °C and let t be the time in minutes, with t = 0 corresponding to the time when the temperature was 87°C.) dy dt = − 1 50
The differential equation below models the temperature of a 87°C cup of coffee in a 23°C room, where it is known that the coffee cools at a rate of 1°C per minute when its temperature is 73°C. Solve the differential equation to find an expression for the temperature of the coffee at time t. (Let y be the temperature of the cup of coffee in °C and let t be the time in minutes, with
t = 0
corresponding to the time when the temperature was 87°C.)
dy
dt
= −
1
50
(y − 23)
With integration, one of the major concepts of calculus. Differentiation is the derivative or rate of change of a function with respect to the independent variable.
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