A watering system holds 500 gallons of water. Water is added into the system at a rate of 8 gallons per minute. 8 gallons of water per minute is removed from the system to water plants. Fertilizer is pumped into the watering system at a rate of 0.08 pounds of fertilizer per gallon of water. Set up the differential equation that models this situation. dF A =0.64 0.016 * F dt dF = 0.64 - 4000 F dt B dF 500 – 0.64 * F dt dF = 0.016 – 0.64 * F dt dF E = 500 - 0.08 F dt

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Given the following situation:
A watering system holds 500 gallons of water. Water is added into the system at a rate of 8 gallons per minute. 8 gallons of
water per minute is removed from the system to water plants. Fertilizer is pumped into the watering system at a rate of
0.08 pounds of fertilizer per gallon of water.
Set up the differential equation that models this situation.
dF
A
= 0.64 – 0.016 * F
dt
dF
= 0.64
dt
B
4000 * F
dF
500 – 0.64 * F
dt
dF
0.016 - 0.64 * F
%3!
dt
dF
= 500 - 0.08 F
dt
E
Transcribed Image Text:Given the following situation: A watering system holds 500 gallons of water. Water is added into the system at a rate of 8 gallons per minute. 8 gallons of water per minute is removed from the system to water plants. Fertilizer is pumped into the watering system at a rate of 0.08 pounds of fertilizer per gallon of water. Set up the differential equation that models this situation. dF A = 0.64 – 0.016 * F dt dF = 0.64 dt B 4000 * F dF 500 – 0.64 * F dt dF 0.016 - 0.64 * F %3! dt dF = 500 - 0.08 F dt E
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