The diagram below shows two long parallel wires, 1 & 2, each carrying a current of 56 A. The direction of the current for each wireis indicated in the diagram. The distance between the wires is 24 cm & the distance between wire 2 & point P is 26 cm. Use thestandard cartesian coordinate system.A.) At P, determine the directions of B, & B2.direction of B, at P = Choose directionChoose directionPdirection of B2 at P ="B.) Determine the x & y components of B, at P.B1X= OTB1YC.) Determine the x & y components of B2 at P.B2xB2yD.) Determine the magnitude & direction of Bnet at P.Bnetdirection of Bneto to the VERTICAL in--- Choose quadrant ---

Answered: The diagram below shows two long…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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The diagram below shows two long parallel wires, 1 & 2, each carrying a current of 56 A. The direction of the current for each wire
is indicated in the diagram. The distance between the wires is 24 cm & the distance between wire 2 & point P is 26 cm. Use the
standard cartesian coordinate system.
A.) At P, determine the directions of B, & B2.
direction of B, at P = Choose direction
Choose direction
P
direction of B2 at P ="
B.) Determine the x & y components of B, at P.
B1X
= OT
B1Y
C.) Determine the x & y components of B2 at P.
B2x
B2y
D.) Determine the magnitude & direction of Bnet at P.
Bnet
direction of Bnet
o to the VERTICAL in
--- Choose quadrant ---

Expert Solution

Step 1

A) we can use right hand curl rule to find the direction of magnetic field:-

Using right hand curl rule we can say that:-

Direction of B₁ at P is i^ or +x axis/rightwards. (Ans)

Direction of B₂ at p is clockwisely ⊥ to the displacement vector between point p and wire 2.

Lets find P-2 (displacement vector between P and wire 2):-

Given:-

Distance between wire 1 and 2= 24 cm

Distance between p and 2= 26 cm

Distance between p and 1= √ (26^2-24^2)= 10 cm

Hence:-

Position vector of P= 10j^

Position vector of 2= 24i^

So, P-2= 10j^ - 24i^

Now to find a vector which is perpendicular to P-2, we can give P-2 a clockwise rotation of 90° and we will achieve the vector that we desire. Hence:-

A= P-2∠90° = -24i^-10j^

And a unit vector along A direction is:-

A^= (-24i^-10j^)/26= B₂^{^} = unit vector along B₂ direction (Ans)

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