The desired final acceleration is now 2g, with a corresponding value for A. Recall: 3 2t 1 T 2t - 3 T a(t) = – Ag 2 Acceleration feels like weight, and a rapid change in acceleration feels like a rapid change in weight. You don't want a too rapid change in weight -- the derivative a'(t) shouldn't be too great. Therefore: • Take the derivative of a(t). • Find t that maximizes a'(t). • Answer T (in seconds) such that the maximum value of a'(t) is 1/50 m/s³. (If this were the actual test, I would give you t. Here, I urge you to figure it out.)

The desired final acceleration is now 2g, with a corresponding value for A. Recall: 3 2t 1 T 2t - 3 T a(t) = – Ag 2 Acceleration feels like weight, and a rapid change in acceleration feels like a rapid change in weight. You don't want a too rapid change in weight -- the derivative a'(t) shouldn't be too great. Therefore: • Take the derivative of a(t). • Find t that maximizes a'(t). • Answer T (in seconds) such that the maximum value of a'(t) is 1/50 m/s³. (If this were the actual test, I would give you t. Here, I urge you to figure it out.)

Name: The desired final acceleration is now 2g, with acorresponding value f
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Description: The desired final acceleration is now 2g, with acorresponding value for A. Recall:3(÷-)-2t2ta(t) = – AgTTAcceleration feels like weight, and a rapid change inacceleration feels like a rapid change in weight. Youdon't want a too rapid change in weigh

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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